To solve this problem you must apply the proccedure shown below:
1. You have the following logarithm:
<span>log(2)n=4
2. Therefore, you con rewrite it as below:
loga(b)=logb/loa
</span>
3. Therefore, you have:
log(2)n=4⇒log(n)/log(2)=4
4. Then, you obtain:
log(n)=4log(2)
5. Therefore, as you can see, the answer for the exercise shown above is the last option, which is:
log(n)=4log(2)
Answer:
Part 1) The area of the shaded region is
Part 2) The area of the shaded region is
Step-by-step explanation:
Part 1) Figure N 1
I assume that the figure ABCD is a square
we know that
The area of the shaded region is equal to the area of the square ABCD minus the area of semicircle BC plus the area of semicircle AD
therefore
The area of the shaded region is equal to the area of the square ABCD
The area of the square is
Part 2) Figure N 2
I assume that the triangle ABC is a right isosceles triangle
so
AB=BC
AB ⊥ BC
The area of the shaded region is equal to the area of triangle plus the area of semicircle
A) <em>Find the area of the triangle ABC</em>
The area of triangle is
substitute
B) Find the area of semicircle
The area of semicircle is equal to
we have
-----> the radius is half the diameter
substitute
therefore
The area of the figure is equal to
The area removed from the sheet of glass after being cut
The area of the sheet of glass after being cut is= x^2 -3x
X=-4
12-3x=24
-12 -12
-3x=12
/-3 /-3
x=-4
Answer: d. 0
Explanation: 5x -5x = 0
0 + 3x =3x
3x - 3x =0