This is what it looks like. It opens to the right.
Answer:
L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft
Step-by-step explanation:
We are given that
Area of rectangular floor=84 square feet
We have to find the possible length and width of for Angelo's clubhouse.
Area of rectangle=
Using the formula
Area of rectangular floor for clubhouse=84 square feet

Factor of 84 are
1,2,4,6,7,12,14,21,42,84
Therefore, possible dimension of rectangular floor

L=1 ft and B=84 ft
L=2 ft and B=42 ft
L=4ft and B=21ft
L=6ft and B=14 ft
L=7ft and B=12ft
L=12 ft and B=7ft
L=14ft and B=6 ft
L=21 ft and B=4 ft
L=42 ft and B=2 ft
L=84 ft and B=1 ft
1 inch = 13.5 feet
5 inches = 5 * 13.5 = 67.5 feet
Answer: AB is 15
Step-by-step explanation: First, you need to draw a picture and label the parts of the line: AB=5x-15; BC= 3x-5; AC =28. Because of the segment addition postulate, you set the equation to be 5x-15+3x-5=28. Then you solve:
5x-15+3x-5=28
Add like terms:
8x-20=28
Add 20 to both sides
8x=48
Divide by 8
x=6
Now, you need to find the measure of AB, so you plug the 6 into the x variable for 5x-15
5(6)-15
30-15
AB=15