3 years ago

SOMEONE HELP ASAP PLEASE ):

1 answer:

4 0

5 becaue its goodflooru

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statuscvo [17]

$log_327=3x+6\\\\log_33^3=3x+6\\\\3=3x+6\\\\3x+6=3\ \ \ /-6\\\\3x=-3\ \ \ /:3\\\\x=-1$

4 0

3 years ago

olasank [31]

200 miles
You just multiply 50 by 4.

:) have a good day !

7 0

3 years ago

nataly862011 [7]

To evaluate a function at a given input, you have to substitute every occurrence of the variable with that particular value.

So, for the first function, you have

$T(x) = -x-2 \implies T(-4) = -(-4)-2 = 4-2 = 2$

The name of the variable is obviously irrelelvant, so the same goes for the second function:

$w(x) = 14-6x \implies w(-3) = 14-6\cdot(-3) = 14 + 18 = 32$

3 0

3 years ago

Anastaziya [24]

Answer:

y=(1/9)x+4

Step-by-step explanation:

x=3b

b=(1/3)x

y=2/6(1/3)x+4

y=(2/18)x+4

y=(1/9)x+4

8 0

3 years ago

lesantik [10]

Answer:

Step-by-step explanation:

20 is divisible by 4, 5 and 10

4 0

3 years ago