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3 years ago

The table shows sets of ordered pairs that form a relation.

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

A relation is a relationship between sets of values. In math, the relation is between the x-values and y-values of ordered pairs. The set of all x-values is called the domain of the relation, and the set of all y-values is called the range of the relation.

A relation from a set X (domain) to a set Y (range) is called a function if each element of X is related to exactly one element in Y.

A. A relation {(2,-3), (3,-3), (1,4), (9,2)} is a function, because each x has exactly one element y related to.

B. A relation {(8,-3), (3,8), (9,4), (-2,2)} is a function, because each x has exactly one element y related to.

C. A relation {(1,-1), (4,8), (9,-1), (3,2)} is a function, because each x has exactly one element y related to.

D. A relation {(1,-1), (-1,5), (1,-6), (-3,2)} is not a function, because x=1 has two possible outcomes y: y=-1 or y=-6.

Answer: A, B and C are functions and D is not a function

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Error in question aside, and ASSUMING the hexagon is regular, you can apply the principle that
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In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known

mote1985 [20]

Answer:

arc BF = 76°
∠M = 31°
∠BGE = 121°
∠MFB = 111°

Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

arc BF = 2∠FBM = 2(38°)

arc BF = 76°

(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

∠M = (1/2)(138° -76°) = 62°/2

∠M = 31°

(c) arc FC is the supplement to arc BF, so has measure ...

arc FC = 180° -arc BF = 180° -76° = 104°

∠BGE is half the sum of arcs BE and FC, so is ...

∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

∠BGE = 121°

(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

∠MFB = 111°

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