Question 2: The answer is A. 90, 45, 45 because one angle is a right angle which is always 90 degrees and the two remaining angles are the same. Also, all triangles have to have a total amount of 180 degrees when all angle-degree-measurements are combined, which leaves A as the only possible answer.
Question 3: The answer is D. To solve this question you simply multiply all the dimensions of the triangular prism together. That would be: 10 x 14 x 8 = 1,120 in squared
Question 4: Sorry, didn't get this one :(
Question 5: The answer is B. 4pi. Sorry, don't have a good explanation for this one, but I'm pretty sure it is correct.
Question 6: Can't see the question, so I can't help you :(
Question 7: The answer is A. 5 feet. Using the power of elimination you can conclude that the three other options to the answer are improbable.
Question 8: The answer is B. 180 - x. To get this you need to know that 180 degrees is a flat line angle. Since angle x and angle y stem from the same two flat lines intersecting diagonally, you can determine the 180 - angle x would equal angle y.
9514 1404 393
Answer:
80
Step-by-step explanation:
If N is the total number of coins, then the number of quarters is ...
36 = 0.45×N
36/0.45 = N = 80
You have 80 coins you your collection.
Answer:
The cashier received 100 envelopes
Step-by-step explanation:
let the number of stamps bought be x.
Cashier will receive 1/3 *x = x/3
Secretary will receive = 1/5 * x = x/5
Now we are told that the secretary received 40 fewer.
This means that the difference between the amounts they received is 40
Mathematically;
x/3 - x/5 = 40
2x/15 = 40
x = (15 * 40)/2 = 600/2 = 300
The cashier received x/3 = 300/3 = 100
The domain is always all real numbers.
HOPE I COULD HELP!
1. (a) The orbital period can be calculated using the equation
T = 2πrr r
gR2
e
where r = Re + h
where re = 6378 km is the earth’s radius, r is the satellites distance
from the earth’s center and h = 205 km is the satellite’s orbital altitude, and g = 9.81m/s2
is the gravitational acceleration. With these
given values the orbital period is
Torbit = 5312.5s = 1.4757h
