You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.
A
Eo = 10^4.4 Joules
E = 2 * 10^15
Formula
M = (2/3) log (E/Eo)
M = 2/3 * log (2 * 10^15/10^(4.4) )
M = 2/3 * log( 7.9621* 10^10)
M = 2/3 * 10.901
M = 7.26735 on the Richter scale. That is a huge amount of energy.
Part B
Suppose that you use Eo and your base. Eo is 10^4.4
Now the new earthquake is E = 10000 * Eo
So what you get now is M = (2/3)* Log(10000 * Eo / Eo )
The Eo's cancel out.
M = 2/3 * log(10000)
M = 2/3 of 4
M = 8/3
M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.
What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667
Answer: M = 2.6667
10^[ 12 - ( - 3 ) ] = 10^( 12 + 3 ) = 10^15 ;
We use the formula
:
Step-by-step explanation:
De qué forma how is your night give me a picture
Answer:
Add
−
1
and
2
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2
,
2
s
+
1
Step-by-step explanation:
Answer:
8(n + 1)
30(t + 1)
56(v + 1)
Step-by-step explanation:
(4n + 4)(2)
4(n + 1)(2)
8(n + 1)
(10t + 10)(3)
10(t + 1)(3)
30(t + 1)
(7v + 7)(8)
7(v + 1)(8)
56(v + 1)
