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Marizza181 [45]
3 years ago
9

Could someone show me how to do this?

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Step-by-step explanation:

b - no:of students on bus

V - " " on van

so the eqtn is

12v+10b=698

14v+2b=244

so when you solve these two eqtns you get

V=9

b=59

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(Question 2) please help.
juin [17]

the radius would be undefined for this problem

3 0
3 years ago
Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi
Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = \frac{\sigma}{\sqrt{n} } \\= 15

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

=P(790

(b) less than 785 hours

=P(X

, (c) more than 820 hours,

=P(X>820)\\=p(Z>1.333)\\= 0.0913

(d) between 770 and 830 hours

=P(|Z|

4 0
3 years ago
Let S = {1, 4, 6, 9}
tankabanditka [31]

Answer:

There are 8 sets B that satisfy the conditions.

Step-by-step explanation:

We have to find the total subsets of S that have 1 as an element.

Subsets B with one element: {1}

Subsets with two elements: {1,4}, {1,6}, {1, 9}

Subsets with three elements: {1,4,6}, {1,4,9}{1,6,9}

Subsets with four elements: {1,4,6,9}

Therefore, B = {1, {1,4}, {1,6}, {1, 9}, {1,4,6}, {1,4,9}, {1,6,9}, {1,4,6,9}}

6 0
3 years ago
The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0
3 years ago
The sum of 18 and twice a number use n to rep<br> Repesent unknown number
Romashka-Z-Leto [24]

18+2n. For sure hope it helps

7 0
4 years ago
Read 2 more answers
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