<span>To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
</span><span>We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
</span><span>Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.</span>
Answer:
Perimeter=22 m
Step-by-step explanation:
Perimeter Of A Figure
Perimeter is the distance measured around a shape. If the figure is line-shaped, the perimeter can be obtained by adding the individual lengths of each segment around the shape.
The figure shown is surrounded by line segments. We only have to add them all to find the perimeter. But we don't need each individual length to do so. We may notice the following (given all angles are right):
The sum of HG+FE+DC equals AB. So the upper and lower lengths are twice AB, or equivalently: 2*7 1/2 m =15 m
It can also be noted that AH+GF=BC+DE=2 1/4+1 1/4 = 3 1/2 m. It means that the two lateral lengths are twice this value: 2* 3 1/2 = 7 m
Thus, the total perimeter is 15 m + 7 m = 22 m
Answer:
Terms must have the same variable (letter) and the same exponent (little number)
(7x² +3y+ 5) +(9x²+11y- 2)
Opening bracket
7x²+3y+5+9x²+11y-2
keeping like terms together
7x²+9x²+3y+11y+5-2
Since terms having same variable and exponent can be subtracted, added,divided and multiplied
So
Solving like terms we get
<u>16x²+14y+3</u> which is a correct answer.
I remember doing this one and its c
