Step-by-step explanation:
This may be the answer to your equation.
Find the quotient of 9/2 ÷3/8 using the algorithm with reciprocal of fractions.
1 answer:
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ANSWER:
STEP-BY-STEP EXPLANATION:
Rational numbers are all numbers that can be expressed as a fraction, that is, as the quotient of two whole numbers.
Therefore, an example would be:
The correct option that depicts the centroid of the triangle is; C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
<h3>How to interpret the segments formed from Triangle Centroid?</h3>The center of inscribed circle into the triangle is the point where the angle bisectors of the triangle meet.
The center of the circumscribed circle over the triangle is the point where the perpendicular bisectors of the sides meet.
Line segments ZE, FY and GX are both angle bisectors and perpendicular bisectors of the sides. Thus, the point of intersection of line segments ZE, FY and GX is the center of inscribed circle into the triangle and the center of the circumscribed circle over the triangle.
Inscribed circle passes through the points X, Y and Z. Circumscribed circle passes through the points E, F and G. So, point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
Thus, the correct option is option C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
Read more about Triangle Centroid at; brainly.com/question/7644338
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Answer:
Step-by-step explanation:
Here you are require to find the equation of the hyperbola given that the center (h,k), the coordinates of the vertices and those of the co-vertices can be determined from the diagram given
The sharp turning points of the curves give the vertices at (-4,2) and (6,2)
Joining the vertices with a straight line will form the transverse axis with length 2a .
To find the length of the transverse axis 2a will be ; 6--4=10. 2a=10 hence a=10/2 =5
a=5
Find the center of the hyperbola at (h,k) by finding the intersecting point of the diagonals of the rectangle in the diagram
The center identified will be (h,k) = (1,2)
To find the length of the conjugate axis 2b will be ; the length between points (1,4) and (1,0) which are the coordinates of the co-vertices in the hyperbola. 2b= 4-0=4 , b=4/2 = 2
b=2
The standard equation of the hyperbola with center (h,k) is written as ;
where (h,k) is center of hyperbola, (h±a,k) is coordinate of the vertices and (h,k±b) are coordinates of co-vertices.
Substitute values of a, b, h, and k in equation as