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aev [14]
4 years ago
15

81 y + 12 when y = 1/9

Mathematics
2 answers:
aivan3 [116]4 years ago
8 0
The answer is 21.
1. Replace the 1/9
2. Multiply 81 and 1/9
3. Then add what u get to 19

Bezzdna [24]4 years ago
5 0

Answer:

21

Step-by-step explanation:

first you simply plug it in

81(1/9)+12

simplify and evaluate

9+12

21

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If 16 candy bars cost $20,how much do 24 candy bars cost.?​
vichka [17]
If 16 candy bars is $20, then each candy bar is $1.25, which means 24 candy bars would cost $30.
3 0
3 years ago
Mike's age is six more than two times his sister's age. Mike is seventeen years old.Write the equation that could be used to det
photoshop1234 [79]

Answer:

Mike's sisters age is 5 years old

Step-by-step explanation:

Since Mike is 17 years old, he is six years older than 2 times her age, so we subtract 6 from his age; we get 11 since he is 2 times her age divide 11 by 2 = 5.5. That means that his sister is 5 years old

8 0
3 years ago
A box is contructed out of two different types of metal. the metal for the top and bottom, which are both square, costs $3 per s
zysi [14]

Let x ft be the length of the base square and y ft be the height of the box.

The volume of the box is

V=x\cdot x\cdot y\ ft^3.

Since the box has a volume of 15 cubic feet, then

x^2y=15,\\ \\y=\dfrac{15}{x^2}.

You need to construct two squares from the metal that cost $3 per square foot.

The area of each square is x^2\ ft^2 and the total cost for these two squares is 2\cdot x^2\cdot 3=6x^2.

The area of each side face is x\cdot y=x\cdot \dfrac{15}{x^2}=\dfrac{15}{x}. Then the total cost for sides is 4\cdot \dfrac{15}{x}\cdot 10=\dfrac{600}{x}.

Let S(x) be the function that represents total cost of the box, then

S(x)=6x^2+\dfrac{600}{x}.

Find the derivative:

S'(x)=12x-\dfrac{600}{x^2}.

When S'(x)=0, then 12x-\dfrac{600}{x^2}=0,\\ \\12x^3=600,\\ \\x^3=50,\\ \\x=\sqrt[3]{50}\ ft.

The dimensions of the box are:

length and width - \sqrt[3]{50}\ ft

height - \dfrac{15}{\sqrt[3]{2500}}\ ft.

4 0
3 years ago
Find the x-intercept and y-intercept of the line. -3x+6y=11
ryzh [129]

Answer:

x- intercept is at ( - 3 \frac{2}{3} ,0).

y- intercept is at (0,1 \frac{5}{6} ).

Step-by-step explanation:

The x-intercept occurs when y=0.

Thus, substitute y= 0 into the equation to find the x- intercept.

-3x +6y= 11

When y= 0,

-3x +6(0)= 11

-3x= 11

x= 11 ÷ (-3)

x =  -  \frac{11}{3}  \\ x =  - 3 \frac{2}{3}

The y-intercept occurs at x= 0.

When x= 0,

-3(0) +6y= 11

6y= 11

y= 11÷ 6

y = 1\frac{5}{6}

3 0
3 years ago
Please help asap due today !!
Allisa [31]

Answer: B

Step-by-step explanation:

Just square the variables outside the square root and multiply them with 5a.

7 0
3 years ago
Read 2 more answers
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