Question

Find the x-intercept and y-intercept of the line. -3x+6y=11

Answer 1

Answer:

x- intercept is at $( - 3 \frac{2}{3} ,0)$.

y- intercept is at $(0,1 \frac{5}{6} )$.

Step-by-step explanation:

The x-intercept occurs when y=0.

Thus, substitute y= 0 into the equation to find the x- intercept.

-3x +6y= 11

When y= 0,

-3x +6(0)= 11

-3x= 11

x= 11 ÷ (-3)

$x = - \frac{11}{3} \\ x = - 3 \frac{2}{3}$

The y-intercept occurs at x= 0.

When x= 0,

-3(0) +6y= 11

6y= 11

y= 11÷ 6

$y = 1\frac{5}{6}$