Again,im not quite sure that i understand what youre asking,will you please specify so that i may answer
Parameterize this surface (call it
) by

with
and
. The limits on
should be obvious. We find the upper limit for
by solving for
where the sphere and cone intersect:




Take the normal vector to
to be

(orientation does not matter here)
Then the area of
is



Answer:
3,-3) becomes ; (3 + 5 , -3-12) ; (8,-15)
(7,-10) becomes;( 7 + 5, -10-12) ; (12,-22)
(13,-14) becomes (7 + 13, -14-10) ; (20,-24)
Step-by-step explanation:
What we have to do here is to add 5 to the x-axis value and subtract 12 from the y-axis value
(3,-3) becomes ; (3 + 5 , -3-12) ; (8,-15)
(7,-10) becomes;( 7 + 5, -10-12) ; (12,-22)
(13,-14) becomes (7 + 13, -14-10) ; (20,-24)
If you simplify, you get
3/2x=3
3x=6
x=2
Answer 1:
<em>1.23456789 × (10-6) = 4.93827156</em>
Answer 2:
<em>(1.23456789 × 10) - 6 = 6.3456789</em>
Answer 3:
<em>1.23456789 × </em>
<em>= 0.000000123456789</em>
<em>Hope this helped! :)</em>