289 196 248 379 319 276 198 349
(in order) 196, 198, 248, 276, 289, 319, 349, 379 there are eight numbers.
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196, 198, 248, 276
since the median is between 198 and 248, we must add both numbers together and divide them by two:
(198 + 248) ÷ 2
= 446/2
<h2>
= 223 (first quartile)</h2>
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289, 319, 349, 379
since the median is between 319 and 349, we must add both numbers together and divide them by two:
(319 + 349) ÷ 2
= 668/2
<h2>
= 334 (third quartile)</h2>
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Interquartile range:
<h2>
IQR: 334 - 223 = 111 </h2>
<em>I double-checked my answers btw</em>
Answer: 45mph
Step-by-step explanation: to solve this, all you have to do is add all of your data, and divide it by the number amount of data you have
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).
The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).
b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.
c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.
Answer:
This probability is 5/7
Step-by-step explanation:
Rewriting this problem may make it appear to be more manageable.
The probability that the number is a solution of 3x-4 < 1 simplies to "x < 5".
This probability is 5/7, since {0, 1, 2, 3, 4} are all less than 5.