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3 years ago

I need HELPPPPPOP PLS HELLLLPPPPPP NOOOOOWWWWWW tysm!!

Mathematics

1 answer:

inysia [295]3 years ago

5 0

Step-by-step explanation:

3÷5%=3÷5÷100

3÷5×1÷ 100

3÷5=3÷500

therefore 3÷5%=3÷500

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Triangle D E F is shown. The length of E F is 10, the length of D F is 7, and the length of D E is 12. What information relevant

Zarrin [17]

Answer:

34.98 square units.

Step-by-step explanation:

It is given that DEF is a triangle, EF=10, DF=7 and DE=12.

Information of sides of triangle is relevant to calculating area.

We should use Heron's formula.

According to Heron's formula, the area of triangle is

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where,

$s=\dfrac{a+b+c}{2}$

For triangle DEF, let a=10, b=7 and c=12.

Now,

$s=\dfrac{10+7+12}{2}=\dfrac{29}{2}=14.5$

Area of triangle is

$A=\sqrt{14.5(14.5-10)(14.5-7)(14.5-12)}$

$A=\sqrt{14.5(4.5)(7.5)(2.5)}$

$A=\sqrt{1223.4375}$

$A=34.977671$

$A\approx 34.98$

Therefore, the area of triangle DEF is 34.98 square units.

8 0

4 years ago

Read 2 more answers

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Vikentia [17]

Answer:

........ not a question but okay

Step-by-step explanation:

5 0

4 years ago

Starting at the 6th floor, an elevator went down 1 floor, up 6 floors, and then down 4 floors. Find the number of the floor on w

Ymorist [56]

Answer:

The answer is that the elevator stopped at the 7th floor

Step-by-step explanation:

6 0

3 years ago

The results of Accounting Principals’ latest Workonomix survey indicate the average American worker spends $1092 on coffee annua

Nataly_w [17]

Answer:

Group 18-34 years old

$\bar x = 1041.625 \\ s^2=485301 \\ s=696.635$

Group 35-44 years old

$\bar x = 1359.5 \\ s^2=178548 \\ s=422.549$

Group 45 and older

$\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248$

According to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average, 47.74% probability that a person between 35 and 44 consume more than the average and 50% probability that a person older than 45 consume more than the average.

Step-by-step explanation:

The mean for each sample is

$\bar x=\frac{\sum_{k=1}^{10}x_k}{10}$

where the $x_k$ are the data corresponding to each group

The variance is

$s^2=\frac{\sum_{k=1}^{10}(\bar x-x_k)^2}{9}$

and the standard deviation is s, the square root of the variance.

Group 18-34 years old

$\bar x = 1041.625 \\ s^2=485301 \\ s=696.635$

Group 35-44 years old

$\bar x = 1359.5 \\ s^2=178548 \\ s=422.549$

Group 45 and older

$\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248$

Let's compare these averages against the general media established of $1,092 by using the corresponding z-scores

$z=\frac{\bar x-\mu}{s/\sqrt{n}}$

where

$\bar x$ = mean of the sample

$\mu$ = established average

s = standard deviation of the sample

n = size of the sample

z-score of Group 18-34 years old

$z=\frac{1041.625-1092}{696.635/\sqrt{10}}=-0.2286$

The area under the normal curve N(0;1) between -0.2286 and 0 is 0.0904. So according to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average.

z-score of Group 35-44 years old

$z=\frac{1359-1092}{422.5491/\sqrt{10}}=2.0019$

The area under the normal curve N(0;1) between 0 and 2.0019 is 0.4774. So according to the sample there is 47.74% probability that a person between 35 and 44 consume more than the average.

z-score of Group 45 and older

$z=\frac{1414.375-1092}{135.2489/\sqrt{10}}=7.5375$

The area under the normal curve N(0;1) between 0 and 7.5375 is 0.5. So according to the sample there is 50% probability that a person older than 45 consume more than the average.

3 0

4 years ago

Please answer honestly and I will give brainleyest

denis-greek [22]

Answer:

I select the third option and the last linear equation

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3 years ago

I need HELPPPPPOP PLS HELLLLPPPPPP NOOOOOWWWWWW tysm!!​

I need HELPPPPPOP PLS HELLLLPPPPPP NOOOOOWWWWWW tysm!!