Given: f(x) = x2 + 8x – 9 g(x) = x² – 2x + 15 What is f(x) – g(x)?
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Since the sum of the numbers on the three draws is 12, if we want the card numbered 2 to be drawn exactly two times, the third card can only be numbered 8. In fact, , and there are no other possibilities, unless you consider the various permutations of the terms.
So, we have three favourable cases: we can draw 2,2,8, or 2,8,2, or 8,2,2. This are the only three cases where the card numbered 2 is drawn exactly two times, and the sum of the number on the three draws is 12.
Now, the question is: we have three favourable cases over how many? Well, we have 5 possible outcomes with each draws, and the three draws are identical, because we replace the card we draw every time.
So, we have 5 possible outcomes for the first draw, 5 for the second and 5 for the third. This leads to a total of possible triplets.
Once we know the "good" cases and the total number of possible cases, the probability is simply computed as
You need to find the circumference of the whole circular pool and then subtract from it the arc length that is 1/4 of the circumference. The circumference formula is C = (3.14)(d), which in our case is 3.14(40) which is 125.6. Now we need the arc length we need to take away. 1/4 of a circle corresponds to a 90 degree angle, so in the formula for arc length, we have this: 
which equals 31.4. Now subtract that from the circumference of the whole circle and you get the outside of the circle minus that arc length. That's 94.2. But we have to go in the radius times 2 to enclose the pie shaped piece we cut away. So we have 134.2. She should've just stuck with enclosing the circle; she would have used less fencing!