They are both group 1 elements and so therefore:
(1) one electron in the outermost shell
Answer:
2.2 % and 0 %
Explanation:
The equation we will be using to solve this question is:
N/N₀ = e⁻λ t
where N₀ : Number of paricles at t= 0
N= Number of particles after time t
λ= Radioactive decay constant
e= Euler´s constant
We are not given λ , but it can be determined from the half life with the equation:
λ = 0.693 / t 1/2 where t 1/2 is the half-life
Substituting our values:
λ = 0.693 / 55 s = 0.0126/s
a) For t = 5 min = 300 s
N / N₀ = e^-(0.0126/s x 300 s) = e^-3.8 = 0.022 = 2.2 %
b) For t = 1 hr = 3600 s
N / N₀ = e^-(0.0126/s x 3600 s) = 2.9 x 10 ⁻²⁰ = 0 % (For all practical purposes)
Answer: The mass percent is 0.064%
Explanation:
To calculate the mass percent of solute in a given solution, we use the formula:
Mass of sugar (solute) = 32 g
Mass of solvent = 50 kg = 50000 g ( 1kg=1000g)
Putting values in above equation, we get:
Hence, the mass percent is 0.064%
