Answer:
the container is 1/4 full at 9:58 AM
Step-by-step explanation:
since the volume doubles every minute , the formula for calculating the volume V at any time t is
V(t)=V₀*2^-t , where t is in minutes back from 10 AM and V₀= container volume
thus for t=1 min (9:59 AM) the volume is V₁=V₀/2 (half of the initial one) , for t=2 (9:58 AM) is V₂=V₁/2=V₀/4 ...
therefore when the container is 1/4 full the volume is V=V₀/4 , thus replacing in the equation we obtain
V=V₀*2^-t
V₀/4 = V₀*2^-t
1/4 = 2^-t
appling logarithms
ln (1/4) = -t* ln 2
t = - ln (1/4)/ln 2 = ln 4 /ln 2 = 2*ln 2 / ln 2 = 2
thus t=2 min before 10 AM → 9:58 AM
therefore the container is 1/4 full at 9:58 AM
First, when multiplying percents, you need to convert them to decimals. You convert percents to decimals by multiplying by 100 or moving the decimal two places to the left. Once you convert them to full decimals, you multiply the decimal by the number that you are getting the percentage from
61% of 180⇒.61×180=<u>109.8 </u>
5.1% of 81?⇒.051×81=<u>4.131
</u>

of 36?⇒16.5×36⇒.165×36=<u>5.94
</u>81% of 241⇒.81×241=<u>195.21</u>
76% of 600⇒.76×600=<u>456</u>
88% of 680⇒.88×680=<u>598.4</u>
37% of 481⇒.37×481=<u>177.97</u>
19.1% of 380⇒.191×380=<u>72.58</u>
41% of 321⇒.41×321=<u>131.61</u>
33% of 331⇒.33×331=<u>109.23</u>
Answer:
Step-by-step explanation:
ayooo u on a real test
Answer:
x=13
Step-by-step explanation:
i don't know if that is right
Answer:
Actual Height = 27.11 m
Step-by-step explanation:
Given:
Height of model rocket = 4.5 % of actual Height
Model Height = 1.22 m
To Find:
Actual Height of rocket = ?
Solution:
We have to Find the Actual Height of the rocket
Let actual height be x
Now it is given that
Height of model rocket = 4.5 % of actual Height
As we have the values so putting it in it becomes
1.22 = 4.5 % * x
it could be written as

Multiplying both sides by 
it becomes
1.22*
= x
= x
27.11 m =x
or
Actual Height = 27.11 m