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patriot [66]
3 years ago
10

Find the derivative of f(y)=9tan(y)-\sqrt{y}/4-10/y^5\sqrt{y}[/tex]

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

f'(y) = 9sec^2(y)-\frac{1}{8\sqrt{y} } - \frac{5y^5\sqrt{y}  - 50y^4\sqrt{y}  }{y^{10}} or any equivalent form

Step-by-step explanation:

rewriting the equation to contain only exponents no roots

f(y)= 9tan(y)-\frac{1}{4} y^\frac{1}{2}  -\frac{10y^\frac{1}{2}}{y^5}

using power rule, quotient rule, and trig derivatives

f'(y) = 9sec^2(y)-\frac{1}{8\sqrt{y} } - \frac{\frac{5y}{\sqrt{y}}(y^5) - 5y^4(10y^\frac{1}{2}) }{y^{10}}

f'(y) = 9sec^2(y)-\frac{1}{8\sqrt{y} } - \frac{5y^5\sqrt{y}  - 50y^4\sqrt{y}  }{y^{10}}

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A school requires 2 computers for every 5 students. If a school has 145 students, how many computers do they need?
defon

Step-by-step explanation:

145/5=23

23×2=46 computers

4 0
3 years ago
Karen purchased the DVD
9966 [12]

Answer:

Percent markdown = 14%

Step-by-step explanation:

Given:

Original price of DVD player = $175.90

Markdown price of DVD player =$153.77

To find percent markdown.

Amount of mark down =\textrm{Original price - Markdown price}=\$175.90-\$153.77=\$22.13

Percent markdown =\frac{Amount\ of\ markdown}{Markdown\ price}\times100=\frac{22.13}{153.77}\times 100=14.39\%\approx 14\%

4 0
3 years ago
help. If 20 men can survive for 24 days on 15 cans of rations, how many cans will be needed for 16 men to survive for 36 days?
Semmy [17]

Answer: 29 cans.

Step-by-step explanation:

20 can survive 24 days with 15 cans.

If X is the number of days that a man can survive with one can of rations.

so X is in the units can/day

then we have that:

24/15*X = 20

X = 20*15/24 = 12.5

This means that a man can live 12.5 days with a can of food.

then, for 16 men and 36 days we have:

(36/C)*12.5 = 16

C = (36/16)*12.5 = 28.1215

And we can not have a 0.1215 of a can, so we should round it up to 29 cans.

4 0
2 years ago
Determine the inverse of the function f (x) = 4(x − 3)2 + 2. inverse of f of x is equal to 3 minus the square root of the quanti
Elodia [21]

The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

4 0
2 years ago
Please help, I don't know how to do this and need it done quickly, thanks for your help and time! have a good day :)
Olenka [21]
Sin50° = BC/3
3sin50° = BC
BC = 2.981
Hope this helped!
7 0
3 years ago
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