Ask question

Ask question

All categories

2 years ago

6

What is the simplified answer to this? thank you :)

mula1" title="9 \sqrt{245} " alt="9 \sqrt{245} " align="absmiddle" class="latex-formula">

1 answer:

Svetradugi [14.3K]2 years ago

6 0

Answer:

$63 \sqrt[ \: ]{5}$

Step-by-step explanation:

$9 \sqrt{245}$

$9 \sqrt{ {7}^{2} \times 5 }$

$9 \times 7 \sqrt{5}$

$63 \sqrt{5}$

You might be interested in

Thomas is opening a savings account. Which integer represents his possible balance after making a deposit?

Ray Of Light [21]

10 is the answer …………..

8 0

2 years ago

Read 2 more answers

Please help me it’s due today at 4:20pm please help me please please help me

Sergio039 [100]

Answer:

x = 3, the error is that the -2x should be added.

Step-by-step explanation:

The -2x should be added to the left side.

3x - 7 = -2x + 8

3x + 2x = 8 + 7

5x = 15

x =3

Answer lest edited 3:11 PM Central, 11/24/2020

4 0

2 years ago

Read 2 more answers

9.296 times 10 to the 7th power in standard form

Volgvan

The answer is 9,2960000

6 0

1 year ago

Solve and simplify 25 x 1/5 (thanks)

sammy [17]

Answer:

5

Step-by-step explanation:

First let turn 25 into a fraction

$\frac{25}{1}*\frac{1}{5}$

Multiply

$\frac{25}{5}$

Divide/Simplify

$=5$

Answer = 5

[RevyBreeze]

4 0

1 year ago

Show why the following statement is true:<br> 2^−1/2 = 1/2^1/2

Alik [6]

In order to solve a negative exponent, you have to consider the multiplicative inverse of the base:

$a^{-m}=\dfrac{1}{a^m}=\left(\dfrac{1}{a}\right)^m$

So, if we solve the negative exponent on the left hand side, we have

$2^{-\frac{1}{2}}=\dfrac{1}{2^\frac{1}{2}}=\left(\dfrac{1}{2}\right)^{\frac{1}{2}}$

which is the right hand side.

6 0

2 years ago