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miss Akunina [59]
3 years ago
13

1.Simplify. 2.Simplify. 3.Which statement best reflects the solution(s) of the equation?

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer to question 1


We want to simplify


\frac{\frac{4x}{5+x}}{\frac{6x}{x+2}}


Let us change the middle bar to a normal division sign by rewriting the expression to obtain,


\frac{4x}{5+x} \div \frac{6x}{x+2}



We now multiply the first fraction by the reciprocal of the second fraction to get,




\frac{4x}{5+x} \times \frac{x+2}{6x}


We cancel out common factors to obtain,



\frac{2}{5+x} \times \frac{x+2}{3}


We multiply out to obtain,




\frac{2(x+2)}{3(x-5)}



ANSWER TO QUESTION 2


We want to simplify,


\frac{\frac{x^2+4x+3}{2x-1}}{\frac{x^2+x}{2x^2-3x+1}}



Let us change the middle bar to a normal division sign by rewriting the expression to obtain,


\frac{x^2+4x+3}{2x-1}\div \frac{x^2+x}{2x^2-3x+1}



We now multiply the first fraction by the reciprocal of the second fraction to get,


\frac{x^2+4x+3}{2x-1}\times \frac{2x^2-3x+1}{x^2+x}



We now factor to obtain,


\frac{(x+1)(x+3)}{2x-1}\times \frac{(x-1)(2x-1)}{x(x+1)}



We now cancel out common factors to obtain,


\frac{(x+3)}{1}\times \frac{(x-1)}{x}



We now multiply out to get,


\frac{(x-1)(x+3)}{x}



ANSWER TO QUESTION 3



We want to solve the equation,



\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}


We need to multiply through by least common multiple of the denominators which is ,


x(x-1)





x(x-1) \times \frac{1}{x-1}+x(x-1) \times \frac{2}{x}=x(x-1) \times \frac{x}{x-1}



x+2(x-1)=x(x)


x+2x-2=x^2





3x-2=x^2






x^2-3x+2=0



(x-1)(x-2)=0



x=1,x=2


But x=1 does not satisfy the equation. It will result in division by zero which is undefined. This is an extraneous solution.



Therefore x=2 is the only solution.


The correct answer is D.










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