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zlopas [31]
3 years ago
6

I cant do this pls help

Mathematics
2 answers:
KengaRu [80]3 years ago
4 0
The distance is 5. Hope this helps!

Vinil7 [7]3 years ago
3 0
Distance is 5 ( I apologize if the answer is wrong )
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Romashka [77]
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5 0
2 years ago
There are 100 students in 11th grade at john d'obryant school of math & science in boston. 60 like basketball and 70 like te
Kryger [21]
I think 70 because playing on a varsity, i think, means to play both sports. So I added 10 to the number of students that play basket ball, which is also equal to the number of students that like tennis.

im not sure
7 0
3 years ago
PLS HELP ME AS SOON AS POSSIBLE
Veseljchak [2.6K]

Answer:

7a. D)

7b. $78

Step-by-step explanation:

7a: We're given the information that there's a daily fee of $50 and $0.35 per mile driven, which is m. We can write "$0.35 per mile driven" as 0.35m. Then, the total amount of money it costs represented as an expression is 50 + 0.35m, thus, making it answer D).

7b: In this problem, we have to take our previous expression 50 + 0.35m, plug in the value of m, and simplify.

  • 50 + 0.35(80)
  • 50 + 28
  • 78

Thus, the answer is $78.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

8 0
2 years ago
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
2 years ago
A 6-foot tall man is standing in front of a school and notices his shadow measures 10 feet. At the same time, he notices the fla
irga5000 [103]

Answer:

The tall of the flag pole is 51 ft answer (A)

Step-by-step explanation:

∵ The tall of the man = 6 ft

∵ The his shadow = 10 ft

∵ The shadow of the flag pole = 85 ft

∵ Tall of the man/tall of the flag = shadow of the man/shadow

   of the flag

∴ 6/x = 10/85 ⇒ where x is the tall of the flag

∴ x = (6 × 85) ÷ 10 = 510 ÷ 10 = 51 ft

∴ The tall of the flag pole is 51 ft

4 0
3 years ago
Read 2 more answers
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