X is 4 be cause the smaller triangle is 1/3 of the bigger one
Answer:
Step-by-step explanation:
The common denominator of
![\frac{3}{4} and \frac{2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20and%20%5Cfrac%7B2%7D%7B6%7D)
is got by taking LCM of 4 and 6 which is 12
Answer:
<h2>
![p = \frac{3r}{4} + q \\](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B3r%7D%7B4%7D%20%20%2B%20q%20%5C%5C%20)
</h2>
Step-by-step explanation:
![r = \frac{4}{3} (p - q)](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20%28p%20-%20q%29)
Multiply through by 3 to eliminate the fraction
That's
![3r = 4(p - q)](https://tex.z-dn.net/?f=3r%20%3D%204%28p%20-%20q%29)
<u>Divide both sides by 4</u>
![\frac{3r}{4} = \frac{4(p - q)}{4} \\ p - q = \frac{3r}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3r%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B4%28p%20-%20q%29%7D%7B4%7D%20%20%5C%5C%20p%20-%20q%20%3D%20%20%5Cfrac%7B3r%7D%7B4%7D%20)
Move q to the other side of the equation to make p stand alone
We have the final answer as
![p = \frac{3r}{4} + q \\](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B3r%7D%7B4%7D%20%20%2B%20q%20%5C%5C%20)
Hope this helps you