Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
Answer:
the solution set consists of {x < -2 ∪ x > 10/3}
Step-by-step explanation:
|3x - 2| > 8 is equivalent to the following set of inequalities:
1) 3x - 2 > 8
and
2) -(3x - 2) > 8
In case 1, above, add 2 to both sides, obtaining 3x > 10, or x > 10/3.
In case 2, above, carry out the indicated multiplication first:
-3x + 2 > 8. Next, subtract 2 from both sides: -3x > 6.
Next, divide both sides by -3, remembering to reverse the direction of the inequality sign: x < -2.
Thus, the solution set consists of {x < -2 ∪ x > 10/3}
Answer:
28 deg
Step-by-step explanation:
Reference angle is the smallest angle formed by the terminal ray, x-axis, and origin. So at 180 you are on the x-axis so just for this question you have to do 180-152=28.
The reference angle should be a positive between 0 and 90 degrees.
Answer:
8-x meters
Step-by-step explanation:
Both 64 and x^2 are perfect squares, since 64=(8)^2 and x^2=(x)^2.
Additionally, 16x is twice the product of the roots of 64 and x^2, since 16x=2(8)(x).
So we can use h the square of a difference pattern to factor:
a^2-2(a)(b)+b^2=(a-b)^2
In this case, a=8 and b=x:
(8)^2-2(8)(x)+(x)^2=(8-x)^2
In conclusion...
64-16x+x^2=(8-x)^2
So the side length of the square is 8-x meters.
Answer:[
−
2
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∞
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,
{
x
|
x
≥
−
2
}
Step-by-step explanation: