If x = 12, then 2(x - 4)^2 =

Mathematics

2 answers:

elena-s [515]3 years ago

5 0

Answer:

128

Step-by-step explanation:

2(x - 4)^2

Let x =12

2 ( 12-4)^2

Do inside the parentheses first

2 (8)^2

Then the exponent

2 * 64

128

Artist 52 [7]3 years ago

4 0

Answer:

128

Step-by-step explanation:

I have answered ur question

You might be interested in

Sherrell mowed 2/5 of the lawn and Trace power 1/3 of it. How much more of the lawn did Sherrell mow than Trace?

Sergeeva-Olga [200]

Sherrell mowed 1/15 more than Trace because when you convert the fractions to equivalent fractions with the same denominator, you get 6/15 and 5/15.

6 0

3 years ago

Tom borrowed $35,000 to remodel his house. At the end of 5-year loan, he had repaid a total of $46,375. At what simple interest

Wewaii [24]

The formula for simple interest is I = prt, where I is the amount of interest, p is the principal borrowed, r is the interest rate written as a decimal number, and t is the amount of time in years. First we find the amount of interest. He borrowed $35000 but paid back $46375. That means he paid 46375-35000 = $11375 in interest. We can now substitute our information into our interest formula:
11375=35000(r)(5)
11375=35000(5)(r) ----- remember that multiplication is commutative
11375=175000r
Divide both sides by 175000 to cancel it:
11375/175000 = 175000r/175000
0.065 = r
To convert this to a percentage, we multiply by 100:
0.065(100) = 6.5%

5 0

3 years ago

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

ad-work [718]

Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}$

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0

3 years ago

What is the equation (simplified) the inverse of y=2x^2?

Yuki888 [10]

$2x^2=y\ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=\dfrac{y}{2}\\\\\boxed{x=\sqrt{\frac{y}{2}}}\\\\x=\dfrac{\sqrt{y}}{\sqrt2}=\dfrac{\sqrt{y}\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\to\boxed{x=\dfrac{\sqrt{2y}}{2}}\\\\\\\boxed{f(x)=2x^2\to f^{-1}(x)=\dfrac{\sqrt{2y}}{2}}$