For this case, what you should see is where the graph cuts the x-axis.
Notice that the graph cuts to the x axis in three different points.
Then the value of x that is in the domain of the function in this case is:
x = 1
For this value of x the function is zero.
Answer:
x = 1
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
First, subtract the numerators and keep the denominator. so it will be 19/8 then turn into a mixed number which will be 16 1/4
Answer:82
Step-by-step explanation:
