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Svetlanka [38]
3 years ago
13

The actual length of a in the triangle shown is 10 cm. Use the scale drawing of the triangle to find the actual length of side b

.
A) 0.18 cm
B) 12.5 cm
C) 16 cm
D) 48.5 cm

Mathematics
2 answers:
Nonamiya [84]3 years ago
5 0
10/1.2 = x/1.5
10 * 1.5 = 15
15/1.2 = 12.5
b = 12.5
wariber [46]3 years ago
4 0

your answer is 12.5!!!

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Two complementary angles are in the ratio of 1:5. find the measure of the larger angle?
Luden [163]
First you set up an equation using a variable:
x + 5x = 90° (complementary angles = 90°)
6x = 90
x = 15 (also the measure of the smaller angle)

now plug in x to find the larger angle:
5(15) = 75°
7 0
3 years ago
Pls <br> helppp<br><br><br> thanks!!!
True [87]

Answer:

64 inch³

Step-by-step explanation:

3 / 2 = 1.5 radius

1.5²x π x 10 = 22.5 π = volume

22.5 π x 9/10 = 20.25π of water

= 63.6172512352

3 0
2 years ago
Pls helpppp!!! I will give brainliest.
pashok25 [27]

Answer:

Step-by-step explanation:

The domain represents the x-values

The range represents the y-values

Domain             Range

  3                        7

                            8

                            -2

                             4

                             1

This relation is not a function because the domain value was used more than one time.  

8 0
2 years ago
Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
Write these numbers in order from least to greatest:<br> -3<br> 6<br> -8<br> -2.5<br> 1/4<br><br> 0
stealth61 [152]

-8, -3, -2.5, 0, 1/4, 6

3 0
3 years ago
Read 2 more answers
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