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galben [10]
2 years ago
11

Question

Mathematics
1 answer:
schepotkina [342]2 years ago
6 0

Answer:

F = \frac{9C + 32}{5}

Step-by-step explanation:

Given

C = \frac{(5F - 32)}{9}

Required

Determine the inverse function

C = \frac{(5F - 32)}{9}

Make F the subject of formula:

Multiply through by 9

9C = 5F - 32

Add 32 to both sides

9C + 32= 5F

Divide through by 5

\frac{9C + 32}{5}= F

F = \frac{9C + 32}{5}

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Heyy!!
rosijanka [135]

<u>Answer:</u>

6^{10}

<u>Step-by-step explanation:</u>

We can use the following rule of surds to solve the problem:

\boxed{a^m \times a^n = a^{m + n}},

which means that when multiplying two numbers with the same bases, we can simply add their powers while keeping the base the same.

Applying this rule:

6^2 \times 6^8

⇒ 6^{2 + 8}

⇒ \bf 6^{10}

8 0
1 year ago
Simplify and leave in radical form. <br> 8√x^2 y^6
IrinaK [193]

Step-by-step explanation:

\sqrt[8]{ {x}^{2}  {y}^{6} }  \\  \\  = ( {x}^{2} {y}^{6}  )^{ \frac{1}{8} }  \\  \\  =  {x}^{2 \times \frac{1}{8}} {y}^{6\times \frac{1}{8}}  \\  \\  = x^{\frac{1}{4}} {y}^{3\times \frac{1}{4}}  \\  \\   = x^{\frac{1}{4}} {y}^{\frac{3}{4}}  \\  \\   =  \sqrt[4]{x {y}^{3} }  \\

4 0
3 years ago
Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis
Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line \overline{AA'} as the  dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}.

7 0
3 years ago
What does a irrational number look like
julia-pushkina [17]

A irrational number is a number that can't be expressed as a ratio of two whole numbers. That's it.

For examples (in increasing order of difficulty)

1 is a rational number because it is 1/1

0.75 is a rational number because it is equal to 3/4

2.333... (infinite number of digits, all equal to three) is rational because it is equal to 7/3.

sqrt(2) is not a rational number. This is not completely trivial to show but there are some relatively simple proofs of this fact. It's been known since the greek.

pi is irrational. This is much more complicated and is a result from 19th century.

As you see, there is absolutely no mention of the digits in the definition or in the proofs I presented.

Now the result that you probably hear about and wanted to remember (slightly incorrectly) is that a number is rational if and only if its decimal expansion is eventually periodic. What does it mean ?

Take, 5/700 and write it in decimal expansion. It is 0.0057142857142857.. As you can see the pattern "571428" is repeating in the the digits. That's what it means to have an eventually periodic decimal expansion. The length of the pattern can be anything, but as long as there is a repeating pattern, the number is rational and vice versa.

As a consequence, sqrt(2) does not have a periodic decimal expansion. So it has an infinite number of digits but moreover, the digits do not form any easy repeating pattern.

5 0
2 years ago
A cube with side length 5h^2 is stacked on another cube with side length 3k What is the total volume of the cubes in factored fo
dalvyx [7]
<span>Just find the volume of each cube separately and add together the results. First cube has side length 5h^2. What is the formula for the volume of a cube? Second cube has side length 3k. Whats its volume?</span>
6 0
3 years ago
Read 2 more answers
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