Answer:
=293.7m²
Step-by-step explanation:
Area of the shaded region = area of the circle-area of the minor segment.
The area of the minor segment is calculated as follows.
Area= Area of sector - area of the triangle bound by the radii.
=∅/360πr²-1/2r²sin∅, where r is the radius of the circle and ∅ the obtuse angle bound by the radii.
=130/360×π×11.1²-1/2×11.1²sin130
=93.43m²
Area of the whole circle =πr²
=π×11.1²
=387.08m²
Area of the shaded region
=387.08m²-93.43m²
=293.65m²
≅293.7m² to the nearest tenth.
Answer:
x = y = 22
Step-by-step explanation:
It would help to know your math course. Do you know any calculus? I'll assume not.
Equations
x + y = 44
Max = xy
Solution
y = 44 - x
Max = x (44 - x) Remove the brackets
Max = 44x - x^2 Use the distributive property to take out - 1 on the right.
Max = - (x^2 - 44x ) Complete the square inside the brackets.
Max = - (x^2 - 44x + (44/2)^2 ) + (44 / 2)^2 . You have to understand this step. What you have done is taken 1/2 the x term and squared it. You are trying to complete the square. You must compensate by adding that amount on the end of the equation. You add because of that minus sign outside the brackets. The number inside will be minus when the brackets are removed.
Max = -(x - 22)^2 + 484
The maximum occurs when x = 22. That's because - (x - 22) becomes 0.
If it is not zero it will be minus and that will subtract from 484
x + y = 44
xy = 484
When you solve this, you find that x = y = 22 If you need more detail, let me know.
Answer:
751000
Step-by-step explanation:
![751 \times (125 \times 2) \times 4](https://tex.z-dn.net/?f=751%20%5Ctimes%20%28125%20%5Ctimes%202%29%20%5Ctimes%204)
![751 \times (250 \times 4)](https://tex.z-dn.net/?f=751%20%5Ctimes%20%28250%20%5Ctimes%204%29)
![751 \times 1000](https://tex.z-dn.net/?f=751%20%5Ctimes%201000)
![751000](https://tex.z-dn.net/?f=751000)
Answer:
its c
Step-by-step explanation: