The half-life of a radioactive kind of tellurium is 40 minutes. How much will be left after 360 minutes if we
2 answers:
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Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
*9
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(*9)*
, or dividing everything by 4.
(*9)/4
Finally, subtract three.
The final equation would read:
((*9)*)-3
Using PE(M/D)(A/S), we'd start with*9
3 and 9 cancel out to be 1 and 3, leaving us with
, or 8, and 3 and this part of the equation reading 8*3, which is 24.
The next step is
, which is 6.
Lastly we subtract 3 from six, leaving us 3.
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(
, or dividing everything by 4.
(
Finally, subtract three.
The final equation would read:
((
Using PE(M/D)(A/S), we'd start with
3 and 9 cancel out to be 1 and 3, leaving us with
The next step is
Lastly we subtract 3 from six, leaving us 3.