The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
brainly.com/question/18797214
#SPJ4
Answer: <em>The answer is 44.</em>
Step-by-step explanation:<em> </em><em>The answer is 44 because if half the area of the circle is 22 all you have to do is 22+22 or 22*2.</em>
<em />
<em>22+22=44 22*2=44</em>
Answer:
x² - 10x + 29
Step-by-step explanation:
The standard form of a quadratic is , ax² + bx + c (a ≠ 0 )
Given
(x - 5)² + 4 ← expand factor using FOIL
= x² - 10x + 25 + 4
= x² - 10x + 29 ← in standard form