The graph has a vertex at (3, -2). It extends upward from there linearly at a slope of -1 to the left and 1 to the right. It is the graph of an absolute value function. If we assume it keeps extending upwards the domain is all real numbers. (which is what i would assume even though there's no arrows it doesn't have decipherable endpoints). The range is y ≥ -2 with y -intercept (0,1), and x-intercepts: (5,0) & (1,0).
To write the equation for this function, I would acknowledge that it is the translation of the graph of the standard absolute value function: f(x) = |x| ; right 3 and down 2. Which would be to subtract 3 from x and subtract 2 from the end.
f(x) = |x - 3| - 2
Yes they are
Composite numbers <span />
Answer:
Step-by-step explanation:
5= 31(x +7)
5= 31x + 217
5 - 217 = 31x + 217 - 217
212 = 31x
212/31 = 31x/31
212 = x
x= 212
Sure he is correct: proof: NOTE TAT 10HRS CORRESPOND TO 100%
1st week he worked 10 hrs, the 10% of 10 is 1 hr. Hence if he worked 11 hrs this week that means 10HRS (100%) + 1HR (10%) =110%
Answer:
- -35/3, -140/3, - 560/3, -2240/3
- 7, -28, 112, - 448
Step-by-step explanation:
<u>The terms are:</u>
<u>Given:</u>
- a₁ = a₂ + 35
- a₃ = a₄ + 560
<u>Use the nth term formula:</u>
- a₂ = a₁r
- a₃ = a₁r²
- a₄ = a₁r³
<u>Substitute:</u>
- a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
- a₁r² = a₁r³ + 560 ⇒ a₁(1 - r)r² = 560
<u>Divide the second equation by the first:</u>
- r² = 560/35
- r² = 16
- r = √16
- r = ± 4
<u>Use the first equation to find the first term:</u>
- a₁( 1 ± 4) = 35
- 1. a₁ = 35/-3 = -35/3
- 2. a₁ = 35/5 = 7
<u>We have two sequences:</u>
r = 4
- -35/3, -140/3, - 560/3, -2240/3
r = -4
