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3 years ago

Which function has a range of {y|y<_5}?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

8 0

Answer:

f(x) = -(x-4)² + 5

Step-by-step explanation:

f(x) = -(x-4)² + 5

Has a maximum vertex at (4,5)

Which means the function has a greatest value of 5 at x = 4

Therefore the range is:

y《5

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If the numerator and denominator of the fraction is increased by 2an1 respectively; it becomes3/4 if the numerator and the denom

ipn [44]

Answer:

The fraction is $\frac{7}{1}$

Step-by-step explanation:

Let the numerator be x and denominator be y

So, Fraction = $\frac{x}{y}$

Now we are given that numerator and denominator of the fraction is increased by 2 and 1 respectively. it becomes 3/4

So, Fraction becomes : $\frac{x+2}{y+1}=\frac{3}{4}$

$4(x+2)=3(y+1)$

$4x+8=3y+3$

$4x-3y+5=0$ ----1

We are also given that the numerator and the denominator are decreased by 2 and 1 respectively , it becomes 1/2

So, Fraction becomes : $\frac{x-2}{y-1}=\frac{1}{2}$

$2(x-2)=y-1$

$2x-4=y-1$

$2x-y-3=0$ ---- 2

Substitute the value of y from 2 in 1

$4x-3(2x-3)+5=0$

$4x-6x+9+5=0$

$14=2x$

$7=x$

Substitute the value of x in 2

$2(2)-y-3=0$

$4-3=y$

$1=y$

So, Fraction = $\frac{x}{y}=\frac{7}{1}$

Hence The fraction is $\frac{7}{1}$

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If ON is a midsegment of KLM, find LM. A.2 B.3 C.4 D.5

Aleksandr-060686 [28]

NO is 2 times LM

2(x+1) = 4x

2x + 2 = 4x

2 = 2x

1 = x

Plug that in for 4x

4(1)

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