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postnew [5]
3 years ago
14

On a number line, which fraction is between 1/4 and 1/5?

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0

Answer:

\dfrac{9}{40}

Step-by-step explanation:

Subtract 1/5 from 1/4, divide by 2, then add to 1/5:

\implies \dfrac{\frac14-\frac15}{2}+\dfrac15

\implies \dfrac{\frac{5}{20}-\frac{4}{20}}{2}+\dfrac15

\implies \dfrac{\frac{1}{20}}{2}+\dfrac15

\implies \dfrac{1}{20} \times \dfrac12+\dfrac15

\implies \dfrac{1}{40}+\dfrac15

\implies \dfrac{1}{40}+\dfrac{8}{40}

\implies \dfrac{9}{40}

Finger [1]3 years ago
5 0

Answer:

7/32

Step-by-step explanation:

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

<u>To find a fraction between 1/4 and 1/5:</u>

1. Make common denominators with both fractions. The larger the <u>common denominator</u>, the more you will find.

2. Choose any fraction between 1/4 and 1/5. That fraction will be in between 1/4 and 1/5.

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

\dfrac{1}{4}\ \text{and }\dfrac{1}{5} \ \rightarrow \ \dfrac{1 \times 40}{4 \times 40}  \ \text{and} \ \dfrac{1 \times 32}{5 \times 32} \ \rightarrow \ \dfrac{40}{160} \ \text{and} \ \dfrac{32}{160}

Now, you may choose any fraction between 40/160 and 32/160.

My chosen fraction is 35/160, which when simplified, gives 7/32.

≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡

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| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

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Answer:

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Step-by-step explanation:

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The corresponding change in y is -2i-2i = -4i.

Use the Pythagorean Theorem to find the length of this line segment:


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