A 9-kilogram bag of sugar cost $27.54. what is the unit price ?

John & friends brought 4 bags of popcorn and 3 sodas at the movie for a total of 13.50. At the next movie John & friend

scoray [572]

Answer:

The cost of 5 bags of popcorn and 2 sodas is 14.25 units.

Step-by-step explanation:

We are given the following in the question:

Let x units be the cost of a popcorn bag and y units be cost of soda.

The cost of 4 bags of popcorn and 3 sodas is 13.50.

Thus, we can write the equation:

$4x + 3y = 13.50$

The cost of 2 bags of popcorn and 5 sodas is 12.00

Thus, we can write the equation:

$2x+5y=12$

Solving the two equations, we get,

$4x + 3y-(4x+10y) = 13.5 - 24\\\Rightarrow -7y =10.5\\\Rightarrow y = 1.5\\\Rightarrow 2x + 5(1.5) = 12\\\Rightarrow x = 2.25$

Thus, the cost of popcorn bag is 2.25 units and the cost of a soda is 1.5 units.

Cost of 5 bags and 2 sodas

= $=5x+2y\\=5(2.25) + 2(1.5)\\=14.25$

Thus, cost of 5 bags of popcorn and 2 sodas is 14.25 units.

8 0

3 years ago

A freight train leaves a station and travels north at 60 mph. 4 hours later, a passenger train leaves on a parallel track and t

harkovskaia [24]

Answer:

first do:

60mph * 4 hours= 240mi

Let D = the distance the passenger train has to

travel to catch the freight train

Start a stopwatch when the passenger train leaves

Let t = the time on the stopwatch when they meet

Equation for freight train:

d-240=60t

Equation for passenger train:

d=100t

all together:

100t-240=60t

we can do 100t-60t because they both have (t)= 40t

40t=240 *now divide 240 by 40= 6

THEN do:

D= 100mph x 6= 600mi

They will meet 600 mi from the station

to check:

d-240=60t x 6

600-240= 360

60 x 6= 360

360=360

5 0

3 years ago

If f(x) = 4x - 3, evaluate f(2).

hjlf

Answer: f(2) = 5

Explanation: If f(x) - 4x - 3, then f(2) = 4(2) - 3 which simplifies to 5.

8 0

3 years ago

Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t

LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

$(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)$