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Ad libitum [116K]
3 years ago
14

solve the system of equations and choose the correct answer from the list of options. 2x y = -4 y = 3x 2(-6/5 , -8/5)(-8/5 , -6/

5)(-6/5 , -11/5)(-11/5 , -6/5)
Mathematics
1 answer:
natita [175]3 years ago
6 0
If you would like to solve the system of equations 2x + y = -4 and y = 3x + 2, you can do this using the following steps:

<span>2x + y = -4
y = 3x + 2
</span>_________
<span>2x + y = -4
</span>2x + 3x + 2 = -4
5x = -4 - 2
5x = -6
x = -6/5

y = 3x + 2 = 3 * (<span>-6/5) + 2 = -18/5 + 10/5 = -8/5
</span>
(x, y) = (-6/5, -8/5)

The correct result would be (-6/5, -8/5).
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If 2x^2+5x-12 = (2x-3)(x+4), which equation(s) should be solved to find the roots of 2x^2+5x-12=0? Check all that apply.
Fynjy0 [20]

ANSWER

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and

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EXPLANATION

Given that:

2 {x}^{2}  + 5x - 12 = (2x - 3)(x + 4)

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2 {x}^{2}  + 5x - 12 = 0

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By the zero product property, we must have either,

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Hence the equations that must be solved to find the roots are:

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