Answer:
![5.10 X +9.00 Y = 831.60](https://tex.z-dn.net/?f=%205.10%20X%20%2B9.00%20Y%20%3D%20831.60)
We also know that for Wedneday we have two times tickets for adults compared to child so we have
![Y =2x](https://tex.z-dn.net/?f=%20Y%20%3D2x)
And using this condition we have:
![5.10 X + 18 X = 831.60](https://tex.z-dn.net/?f=%205.10%20X%20%2B%2018%20X%20%3D%20831.60)
And solving for X we got:
![X= \frac{831.60}{23.1}=36](https://tex.z-dn.net/?f=%20X%3D%20%5Cfrac%7B831.60%7D%7B23.1%7D%3D36)
So then the number of tickets sold for child are 36
Step-by-step explanation:
For this problem we can set upt the following notation
X = number of tickets for child
Y= number of tickets for adults
And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue
![5.10 X +9.00 Y = 831.60](https://tex.z-dn.net/?f=%205.10%20X%20%2B9.00%20Y%20%3D%20831.60)
We also know that for Wedneday we have two times tickets for adults compared to child so we have
![Y =2x](https://tex.z-dn.net/?f=%20Y%20%3D2x)
And using this condition we have:
![5.10 X + 18 X = 831.60](https://tex.z-dn.net/?f=%205.10%20X%20%2B%2018%20X%20%3D%20831.60)
And solving for X we got:
![X= \frac{831.60}{23.1}=36](https://tex.z-dn.net/?f=%20X%3D%20%5Cfrac%7B831.60%7D%7B23.1%7D%3D36)
So then the number of tickets sold for child are 36
The fraction 8/21 cannot be simplified because the numerator and denominator don't have a common factor except 1.
Answer:
6x + 1
Solutions? I don’t know 1? Unless you simplify it which I’m not sure about
Explanation:
3x + 12 = 3x + 4
3x + 3x = 6x
12 + 4 = 16
6x + 16
Ok so form what i can see i belive but not shure that it is positive 7
I think there’s 2 fourths in 2 , I tried my best