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3 years ago

5

Use the graph of the quadratic function y = x2 + x + 4 to answer the question. What are the zeros of the function? –2 and 4 4 an

d 0 4 and –4 –8 and –4

2 answers:

jek_recluse [69]3 years ago

8 0

Answer.

A. -2 and 4

Step-by-step explanation:

If you mean't for the question to really be "Use the graph of the quadratic function y = -1/2x^2 + x + 4 to answer the question.

"

What are the zeros of the function?

–2 and 4

4 and 0

4 and –4

–8 and –4

The answer is A. -2 and 4

(I just took the unit test on e.d.g.e)

otez555 [7]3 years ago

4 0

Answer:

A

Step-by-step explanation:

Just took test

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Find ML, JK=3x+11, ML=10x-12, NP=45

tigry1 [53]

Answer:

$ML = 58$

Step-by-step explanation:

Given

$JK=3x+11, ML=10x-12, NP=45$

See attachment

Required

Length ML

First, calculate x using the following equivalent ratios

$JK : NP = NP : ML$

Express as fraction

$\frac{JK }{ NP} = \frac{NP }{ ML}$

Cross Multiply

$JK * ML = NP * NP$

Substitute values:

$(3x +11) * (10x - 12) = 45 * 45$

Expand

$30x^2 - 36x + 110x - 132 = 2025$

$30x^2 +74x - 132 = 2025$

Collect like terms

$30x^2 +74x - 132 - 2025=0$

$30x^2 +74x -2157=0$

Using a calculator:

$x \approx -10$ and $x \approx 7$

Given that:

$ML=10x-12$

Substitute values for x

$ML=10*-10-12 = -100 - 12 = -112$

$ML=10*7-12 = 70 - 12 = 58$

ML cannot be negative; So:

$ML = 58$

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The derivative of the function f is given by f′(x)=−3x+4 for all x, and f(−1)=6. Which of the following is an equation of the li

Viefleur [7K]

Answer:

The equation of the line tangent to the graph of f at x = -1 is $y = 7\cdot x +13$ .

Step-by-step explanation:

From Analytical Geometry we know that the tangent line is a first order polynomial, whose form is defined by:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - Intercept, dimensionless.

The slope of the tangent line at $x = -1$ is:

$f'(x) = -3\cdot x +4$ (2)

$f'(-1) = -3\cdot (-1) +4$

$f'(-1) = 7$

If we know that $m = 7$ , $x = -1$ and $y = 6$ , then the intercept of the equation of the line is:

$b = y-m\cdot x$

$b = 6-(7)\cdot (-1)$

$b = 13$

The equation of the line tangent to the graph of f at x = -1 is $y = 7\cdot x +13$ .

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3 years ago