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3 years ago

9

Is 0.625 greater than 0.75

1 answer:

adell [148]3 years ago

7 0

Answer:

no

Step-by-step explanation:

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I am stuck on this one and its due tomorrow! Please help

marysya [2.9K]

I believe the error she made was adding it or multipulcation

8 0

3 years ago

V=s^2+ 1/2sh, solve for H.

vladimir1956 [14]

V = s^2 +1/2sh
Reorder so common terms are on one side.
s^2 +(sh)/2 = v
Subtract s^2 from both sides.
(sh)/2 = -s^2 +v
Multiply both sides of the equation by 2.
sh = -s^2 *2 +v *2
Simplify each term.
sh = -2s^2 +2v
Divide each term by s and simplify.

h = -2s + (2v)/s

3 0

3 years ago

Solve the system. find x,y, and z please show all steps<br><br> x-y+z=1<br> x+y+3z=-3<br> 2x-y+2z=0

Mariulka [41]

Solving the system we get, x= -1, y= -2 and z= 0

Step-by-step explanation:

Solving the equations to find x, y and z

$x-y+z=1\,\,\,eq(1)\\x+y+3z=-3\,\,\,eq(2)\\2x-y+2z=0\,\,\,eq(3)$

Adding eq(1) and eq(2)

$x-y+z=1\\x+y+3z=-3\\--------\\2x+4z=-2\,\,\,\,eq(4)\\$

Adding eq(2) and eq(3)

$x+y+3z=-3\\2x-y+2z=0\\----------\\3x+5z=-3\,\,\,eq(5)$

Multiplying eq(4) by 3 and eq(5) by 2

$6x+12z=-6\\6x+10z=-6\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\2z=0\\z=0$

So, value of z =0

Putting value of z in eq(4)

$2x+4z=-2\\2x+4(0)=-2\\2x=-2\\x=-1$

So, value of x = -1

Now putting value of z=0 and x =-1 in equation 1

$x-y+z=1\\-1-y+0=1\\-y=1+1\\-y=2\\y=-2$

So, value of y = -2

So, solving the system we get, x= -1, y= -2 and z= 0

Keywords: Solve the system

Learn more about Solve the system at:

#learnwithBrainly

7 0

3 years ago

Please help me <br> Find the product of ( 5x+2y)( 5x-3y) using the identity.

wel

The product is: 25x^2-5xy-6y^2

3 0

3 years ago

What is the coefficient of the third term in the binomial expansion of (a + b)6? 1 15 20 90

Sholpan [36]

Answer: 15

Step-by-step explanation:

(r+1)th term of $(a+b)^n$ is given by:-

$T_{r+1}=\ ^nC_r(a)^{n-r}b^r$

For $(a+b)^6$ , n= 6

$T_3=T_{2+1}=\ ^6C_2(a)^{6-2}(b)^2\\\\$

$=\ \dfrac{6!}{4!2!}a^4b^2\ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{6\times5\times4!}{4!\times2}a^4b^2\\\\=3\times5a^4b^2\\\\ =15a^4b^2$

Hence, the coefficient of the third term in the binomial expansion of $(a+b)^6$ is 15.

3 0

3 years ago

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