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3 years ago

The figure below shows segments AC and EF which intersect at point B.

Mathematics

2 answers:

Anna007 [38]3 years ago

5 0

Answer:

Choice 3

Step-by-step explanation:

For some reason it doesn't let me put more details

kherson [118]3 years ago

4 0

Answer: C) ∠ A FB ≅ ∠CEB

<u>Step-by-step explanation:</u>

We can prove that Δ ABF ≅ ΔCBE by Angle-Angle (AA) Congruency Theorem.

∠ABF ≡ ∠CBE Vertical Angles Postulate

∠AFB ≡ ∠CEB Alternate Interior Angles Postulate

∠FAB ≡ ∠ECB Alternate Interior Angles Postulate

We only need two of the above statements/reasons above to prove AA Congruency Theorem.

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The speed of sound in air at room temperature is about 343 m/s calculate this speed in feet per minute

Setler [38]

Answer:

67519.7 Feet per minute

Step-by-step explanation:

343 metres per second = 67519.7 feet per minute.

8 0

3 years ago

(10 POINTS AND BRAINLIEST FOR BEST)

Naddik [55]

Answer:

C. II only

Step-by-step explanation:

Basically all you need do is plug these answers in and if the complete the inequality to make a true statement.

Yes i know no body want to do that but that whats need to be done lol.

once i plug 7 12/7+8 = 12.83

12.83>20

is incorrect

so we need continue

7*2.5+8>20

7*2.5= 17.5

17.5+8= 25.5

25.5>20

this a true statement

so we know 2.5 is an answer

now we need plug in -3

7*-3= -21

-21 +8 = -13

-13>20

this is incorrect

6 0

4 years ago

(n – p)^2; use n=5, and p= 3<br>

Bumek [7]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the cube roots of 8(cos 216° + i sin 216°).

Tomtit [17]

$z^3=8(\cos216^\circ+i\sin216^\circ)$
$z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)$
$\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)$

where $k=0,1,2$ . So the third roots are

$z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}$

5 0

3 years ago

Janet can make 3/5 of a necklace in 20 minutes. At this rate, how many necklaces, to the nearest tenth of a necklace, can Janet

Mumz [18]

Answer:

1 4/5 of a necklace, or 1.8 necklaces.

Step-by-step explanation:

As we know, an hour has 60 minutes, and Janet can make 3/5 of a necklace in 20 minutes. 60/20 is 3. So we need to mulitply 3/5 by 3 to get the amount of necklaces she can make in an hour. When we do this, we get 9/5. We can convert this to 1 4/5, and as decimal form, this is 1.8. That is our answer. I hope this helps!

4 0

3 years ago

The figure below shows segments AC and EF which intersect at point B. ​

The figure below shows segments AC and EF which intersect at point B.