Can someone please help me with this question

The length of a rectangle if the length is twice the size of the width increased by one

Alenkasestr [34]

The correct question is
The length of a rectangle if the length is twice the size of the width increased by 1 is it one of the following answers:
A) l= 2w-1
B) l= 2w+1
C) l= 3w
D) none of the choices given

Let
l--------------> length of a rectangle
w-------------> width of a rectangle

we know that
if the length is twice the size of the width increased by 1
l=2w+1

the answer is the option B) l= 2w+1

3 0

4 years ago

How many terms are in 8y+7z

Schach [20]

Everything separated by a '+' or '-' sign separates a term so in this expression there are 2 terms

8 0

3 years ago

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A tornado traveled 260 miles in 4 hours. if the average rate at which the tornado is moving slows by 20%, how many miles will th

lianna [129]

Given that the tornado traveled 260 miles in 4 hours, its initial speed is 65 mi/h. Then, slowing by 20% every hour, the speed after 2 hours can be calculated through the equation,
speed = (65 mi/h) x (1-0.2)^2
speed = 41.6 mi/h
Thus, the speed of the tornado after 2 hours is approximately 41.6 mi/h.

5 0

3 years ago

Read 2 more answers

Please explain as well!

OlgaM077 [116]

I can’t see the picture

4 0

4 years ago

Read 2 more answers

Each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard d

Verdich [7]

Answer:

(a) Between 27 and 31 pounds per month = 0.62465

(b) More than 30.2 pounds per month = 0.1357

Step-by-step explanation:

We are given that each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard deviation is 2 pounds and the variable is approximately normally distributed.

Let X = generation of newspaper for garbage or recycling

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population average = 28 pounds

$\sigma$ = population standard deviation = 2 pounds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability of household generating between 27 and 31 pounds per month is given by = P(27 pounds < X < 31 pounds) = P(X < 31 pounds) - P(X $\leq$ 27 pounds)

P(X < 31 pounds) = P( $\frac{X-\mu}{\sigma}$ < $\frac{31-28}{2}$ ) = P(Z < 1.50) = 0.93319

P(X $\leq$ 27 pounds) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{27-28}{2}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

{Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.50 and x = 0.50 in the z table which has an area of 0.93319 and 0.30854 respectively.}

Therefore, P(27 pounds < X < 31 pounds) = 0.93319 - 0.30854 = 0.62465

(b) Probability of household generating more than 30.2 pounds per month is given by = P(X > 30.2 pounds)

P(X > 30.2 pounds) = P( $\frac{X-\mu}{\sigma}$ > $\frac{30.2-28}{2}$ ) = P(Z > 1.10) = 1 - P(Z $\leq$ 1.10)

= 1 - 0.8643 = 0.1357

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.10 in the z table which has an area of 0.8643.

3 0

4 years ago