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Marysya12 [62]
1 year ago
6

For a parallel structure of identical​ components, the system can succeed if at least one of the components succeeds. Assume tha

t components fail independently of each other and that each component has a 0.21 probability of failure. Complete parts​ (a) through​ (c) below.
Would it be unusual to observe one component​ fail? Two​ components?
It
▼
would not
would
be unusual to observe one component​ fail, since the probability that one component​ fails,

enter your response here​, is
▼
less
greater
than 0.05. It
▼
would not
would
be unusual to observe two components​ fail, since the probability that two components​ fail,

enter your response here​, is
▼
greater
less
than 0.05.
Mathematics
1 answer:
Dennis_Churaev [7]1 year ago
5 0

Using the probability concept, we have that:

a) It would not be unusual to observe one component​ fail, since the probability that one component​ fails is greater than 0.05.

b) It would be unusual to observe two components​ fail, since the probability that two components​ fail is less than 0.05.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>. If a probability is less than 0.05, the event is considered unusual.

In this problem, the probabilities are given as follows:

  • 0.21 probability that one component fails, hence not unusual.
  • (0.21)² = 0.0441 probability that two components fail, hence unusual.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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