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Neko [114]
3 years ago
8

A prime polynomial cannot be written as a product of lower-degree polynomials. Which polynomial is prime? A)8x2 – 10x – 3 b)8x2

+ 2x – 3 c)8x2 – 6x – 3 d)8x2 + 23x – 3
Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

Option (A) and (C).

Step-by-step explanation:

Prime polynomial can't be written as a product of lower degree polynomials.

(A)

8x^2-10x-3

=8x²-6x-4x-3

=2x(4x-3)-1(4x+3)

Here we can't write the polynomial as a product of lower degree.

Therefore it is a prime polynomial.

(B)

8x²+2x-3

=8x²+6x-4x-3

=2x(4x+3)-1(4x+3)

=(4x+3)(2x-1)

Therefore it is not a prime polynomial.

(C)

8x²-6x-3

Therefore it is a prime polynomial.

(D)

8x²+23x-3

=8x²+24x-x-3

=8x(x+3)-1(x+3)

=(x+3)(8x-1)

Therefore it is not a prime polynomial.

Sav [38]3 years ago
3 0

Answer: C. 8x^2-6x-3

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Answer:

After translation:

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After dilation:

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W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

Step-by-step explanation:

Given the vertices of the Quadrilateral WXYZ

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Translation: (x, y)  →  (x-6, y-8)

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W(-4, 8)  →  (x-6, y-8) ⇒ (-4-6, 8-8) = W'(-10, 0)

X(-4, 0)  →  (x-6, y-8) ⇒ (-4-6, 0-8) = X'(-10, -8)

Y(-12, 4)  →  (x-6, y-8) ⇒ (-12-6, 4-8) = Y'(-18, -4)

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W'X'Y'Z' = W'(-10, 0), X'(-10, -8), Y'(-18, -4), Z'(-14, 8)

Next, the rule of dilation is given by

Dilation: (x, y)  →  (2x, 2y), centered at (0, 0)

W'(-10, 0)  →  (2x, 2y) ⇒ (2(-10), 2(0)) = W'' (-20, 0)  

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Z'(-8, 16)  →  (2x, 2y) ⇒ (2(-8), 2(16)) = Z'' (-16, 32)

Therefore,

W''X''Y''Z'' = W'' (-20, 0), X'' (-8, 0) , Y'' (-24, 8), Z'' (-16, 32)

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