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satela [25.4K]
3 years ago
8

The goals of the _________ are to link corporate strategy and IT strategy, approve the allocation of resources for the MIS funct

ion, and establish performance measures for the MIS function and see that they are met.
Computers and Technology
1 answer:
NemiM [27]3 years ago
5 0

Answer:

IT Steering Committee

Explanation:

IT steering committee are committee which purpose is to direct, review and approve IT strategic plans, oversee major initiatives, and allocate resources. The steering committee establishes IT priorities for the business as a whole.

The sole aim or goals of an IT steering committee is to establish performance measures for the MIS function and see that they are met.

IT steering committee also decide on the priorities of business within an organization, and then manage the general course of the operation. Steering committee can change the look of a business.

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What is the name of the virus that appears to be a legitimate program?
timurjin [86]
A virus or malware appearing/pretending to be a legitimate program is called a Trojan. 
3 0
3 years ago
Write a program that lets the user enter the name of a team and then displays the number of times that team has won the World Se
xz_007 [3.2K]

Answer:

see explaination

Explanation:

import java.io.*;

import java.util.Scanner;

public class Winners {

public static void main(String args[]) throws IOException {

Scanner sc = new Scanner(new File("WorldSeriesWinners.txt"));

String commands[] = new String[100000];

int c = 0;

while (sc.hasNextLine()) {

String input = sc.nextLine();

System.out.println(input);

if (input.isEmpty())

continue;

commands[c++] = input;

}

sc.close();

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter the name of a team: ");

String name = keyboard.nextLine();

int count = 0;

for (int i = 0; i < c; i++) {

if (commands[i] != null) {

if (commands[i].equals(name)) {

++count;

}

}

}

if(count!=0)

System.out.println(name + " has won the World Series in the time period from 1903 through 2018 " +count + " number of times" );

else

System.out.println("Team with name "+name+ " does not exists");

}

}

5 0
3 years ago
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
3 years ago
In the main function, define five variables of type int, named: first, second, third, fourth, and total. Also in the main functi
fiasKO [112]

Answer:

  1. import java.util.Scanner;
  2. public class num8 {
  3.    public static void main(String[] args) {
  4.    int first, second, third, fourth,total;
  5.    double decimalOne, decimalTwo, decimalTotal;
  6.    }
  7.    public static void getData(int first, int second, int third, int fourth, double decimalOne, double decimalTwo){
  8.        System.out.println("Enter the Values");
  9.        Scanner in = new Scanner(System.in);
  10.        first=in.nextInt();
  11.        second=in.nextInt();
  12.        third=in.nextInt();
  13.        fourth=in.nextInt();
  14.        decimalOne = in.nextDouble();
  15.        decimalTwo = in.nextDouble();
  16.    }
  17.    public static int computeTotal(int first, int second, int third){
  18.        return first+second+third;
  19.    }
  20.    public static int computeTotal(int first, int second, int third, int fourth){
  21.        return first+second+third+fourth;
  22.    }
  23.   public static double computeTotal(double decimalOne, double decimalTwo){
  24.        return decimalOne+decimalTwo;
  25.    }
  26.    public static void printAll( int first, int second, int third){
  27.        System.out.println("Number one, two and three are: "+first+" "+second+" "+third);
  28.    }
  29.    public static void printAll( int first, int second, int third, int fourth){
  30.        System.out.println("Number one, two and three and four are: "+first+" "+second+
  31.                " "+third+" "+fourth);
  32.    }
  33.   public static void printAll( int first, int second, int third, int fourth, int fifth){
  34.        System.out.println("Number one, two and three and four are: "+first+" "+second+
  35.                " "+third+" "+fourth+" "+fifth);
  36.    }
  37.    public static void printAll( double first, double second, double third){
  38.        System.out.println("Number one, two and three and four are: "+first+" "+second+
  39.                " "+third);
  40.    }
  41. }

Explanation:

This solution is provided in Java:

All the variable declarations are done in the main method (lines 3-6)

Eight methods as specified in the question are created (Lines 7, 17, 20, 23, 26, 29, 33 and 37).

Observe the concept of Method Overloading (i.e. methods with same name and return types but different parameter list)

8 0
3 years ago
What is the only language a microprocessor can process directly but most programmers almost never write programs in this code?
Phantasy [73]
Assembly language, a.k.a. machine language.
6 0
3 years ago
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