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yaroslaw [1]
2 years ago
9

To obtain your class E learner license, youll need too _

Computers and Technology
1 answer:
k0ka [10]2 years ago
8 0
<h3>                                           Answer:</h3>

  To obtain you  class E Learner License,  you'll need to <u>Pass a literacy Test</u>

<h2>         </h2><h2>                 Can you Brainliest me?</h2>
You might be interested in
In the electric series, which one of the following materials is the most negatively charged? A. Silk B. Sealing wax C. Teflon D.
Snowcat [4.5K]
C) Teflon (:


Good luck!
7 0
3 years ago
Read 2 more answers
Which function can you perform on a word processor but not on a typewriter?
zmey [24]
A function you can perform on a word processor BUT NOT on a typewriter is editing.
5 0
3 years ago
Read 2 more answers
Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

Answer:

No you can not tell that recursion is ever required to solve a problem.

Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.

Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

                           Fibonacci(n)

                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

8 0
3 years ago
Lesser-known ideas and interpretations of common knowledge need to be documented. true or false.
Tresset [83]
False. As it is common knowledge, it is unnecessary for it to be documented.
7 0
3 years ago
Write a loop that sets each vector element to the sum of itself and the next element, except for the last element which stays th
Gekata [30.6K]

Answer:

Add the following lines of code to the already existing code segment

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

Explanation:

To do the task in the question, we have to iterate through the vector from the first element i.e. element at index 0 to the second to the last element; i.e. element at last index - 1

We then add each element in this iteration with the next.

This iterates through the vector from 0 to SCORES_SIZE - 1

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>This adds each vector element with the next</em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

The above should be added before

<em>for (i = 0; i < SCORES_SIZE; ++i) { </em>

<em>        cout << bonusScores.at(i) << " "; </em>

<em>}</em>

<em />

<em>Also, I've made other modifications to the program.</em>

  • <em>Proper import of header files</em>
  • <em>Proper declaration of vector bonusScores</em>

<em />

<em>See attachment for complete source code</em>

Download cpp
6 0
3 years ago
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