Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Answer:
B
Step-by-step explanation:
the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.
Answer: 11:11
Step-by-step explanation:
The ratio is 11 nickles to 11 dimes, Take away the names of the coins and there is your answer. (If i'm correct)
First I'd expand the brackets so that you can re-simplify the values, so:
(2x + 3)(3x + 4)
6x^2 + 9x + 8x + 12
6x^2 + 17x + 12
The answer A. 2x(3x + 4) + 3(3x + 4) can be simplified the same way, with 6x^2 + 8x + 9x + 12, and so the answer is A. I hope this helps!