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masya89 [10]
3 years ago
6

The results of a survey are shown in the pie chart below and the survey 28 students say their favorite dessert is ice cream how

many people say their favorite dessert is pie cake: 27% candy: 23% Pie: 15%
Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

12 students.

Step-by-step explanation:

The complete question would be:

If ice cream is the last dessert, then we can solve for how many percent of the students like ice cream. If we add the 4 desserts percent, it should be equal to 100%

Pie : 15%

Candy : 23%

Cake : 27%

Pie% + Candy% + cake% + ice cream% = 100%

15% + 23% + 27% + Ice cream% = 100%

65% + Ice cream% = 100%

Ice cream% = 100% - 65%

Ice cream % = 35%

Percent is a way of saying how many out of a 100. Before we can tell how many students like pie, we need to figure out how many students were surveyed.

It says here that 35% of them like ice cream and among the students, 28 students like ice cream. This means that 28 is 35% of a number, which will be the number of students surveyed.

So as a fraction:

35\% = \dfrac{35}{100}

We need to find a ratio that is proportional to that, with 28 as the part of the whole.

\dfrac{35}{100} = \dfrac{28}{x}\\\\Cross-multiply\\\\35x = 28(100)\\\\35x = 2800\\\\Divide\;both\;sides\;by\;35\\\\\dfrac{35x}{35} = \dfrac{2800}{35}\\\\x=80

So that is the number of students survey. Now to look for how may people like pie, we find what is 15% of 80. So we find the part of the whole this time:

\dfrac{15}{100}=\dfrac{x}{80}\\\\15(80)=100x\\\\1200 = 100x\\\\\dfrac{1200}{100}=\dfrac{100x}{100}\\\\12 = x

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A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

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3 years ago
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musickatia [10]

Answer:

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Step-by-step explanation:

the supplement is the angle that will add to the other angle to get 180 degrees. 180-129=51 which is B.

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Step-by-step explanation:

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