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yKpoI14uk [10]
3 years ago
14

2. Angela is 4 1/2 years older than Tony. Three times Angela's age added to

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:  You see this is q trick question meant to get your brain all confused. IT gives you the answer, It states that Tony is 36 years old and Angela is 4 and 1/2 years older than Tony which would make her 40 1/2 years old.

Step-by-step explanation:

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Please help!!!! I’m unsure of the answers
igomit [66]

Answer:

table:

.1, .25, .35, .2, .1

p(x=4) = .1

p(x<2) = .35

p(3≤x≤4)= .55

1.95, 1.12

Step-by-step explanation:

this is kind of hard to read, but i think i've got it

mean:

0*.1+1*.25+2*.35+3*.2+4*.1= 1.95

The second moment:

0²*.1+1²*.25+2²*.35+3²*.2+4²*.1= 5.05

the variance is the second moment minus the first moment squared (first moment is the mean) and then the standard deviation is the square root of the mean

5.05-1.95²= 1.2475 √1.2475= 1.1169 or 1.12

3 0
3 years ago
What is the number for x
FinnZ [79.3K]
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5 0
4 years ago
Write an equation in point-slope form of the line that has a slope of 10 and passes through (6,2)
GaryK [48]

Answer:

y = 10x - 58

Step-by-step explanation:

y-y1 = m (x-x1)

m= 10

x1= 6

y1 = 2

y - 2 = 10 ( x - 6)

y - 2 = 10x -60

y = 10x - 58

7 0
3 years ago
Which net represents this rectangular prism?
VashaNatasha [74]
When a solid figure is unfolded along its edges and its faces are laid out in two dimensions in a pattern, the net of a solid figure is formed. Rectangular networks of prisms are constructed of rectangles and squares.
6 0
3 years ago
For each of the systems of equations that follow, use Gaussian elimination to obtain an equivalent system whose coefficient matr
noname [10]

Answer:

b) inconsistent

d) inconsistent

f) inconsistent

j) X_1 = 2 - 6a , X_2 = 4 + a , X_3 = 3 - a, X_4 = a (free variable)

Step-by-step explanation:

b)

Given: Augmented matrix

\left[\begin{array}{ccc}2&-3&5\\-4&6&8\end{array}\right]

Row operation : R_2 + 2*R_1

\left[\begin{array}{ccc}2&-3&5\\0&0&18\end{array}\right]

Looking at R_2 : 0 not equal to 18 ; Hence, inconsistent

c)

Given: Augmented matrix

\left[\begin{array}{cccc}3&2&-3&4\\1&-2&2&1\\11&2&1&14\end{array}\right]

Row operation : R_2 <---> R_1

\left[\begin{array}{cccc}1&-2&2&1\\3&2&-3&4\\11&2&1&14\end{array}\right]\\

Row operations : R_2 - 3*R_1   &   R_3 - 11*R_1

\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&24&-21&3\end{array}\right]\\

Row operations : R_3 - 3*R_2  

\left[\begin{array}{cccc}1&-2&2&1\\0&8&-9&1\\0&0&6&0\end{array}\right]\\

Looking at R_3 : 0 not equal to 6 ; Hence, inconsistent

f)

Given: Augmented matrix

\left[\begin{array}{cccc}1&-1&2&4\\2&3&-1&1\\7&3&4&7\end{array}\right]\\

Row operations : R_2 - 2*R_1   &   R_3 - 7*R_1

\left[\begin{array}{cccc}1&-1&2&4\\0&5&-5&-7\\0&10&-10&-21\end{array}\right]\\

Row operations : R_2 --> ( 1 / 5 )* R_2  & R_3 --> ( 1 / 10 )* R_3

\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&1&-1&-2.1\end{array}\right]\\

Row operations : R_3 - R_1

\left[\begin{array}{cccc}1&-1&2&4\\0&1&-1&-1.4\\0&0&0&-0.7\end{array}\right]\\

Looking at R_3 : 0 not equal to -0.7 ; Hence, inconsistent

j)

Given: Augmented matrix

\left[\begin{array}{ccccc}1&2&-3&1&1\\-1&-1&4&-1&6\\-2&-4&7&-1&1\end{array}\right]\\

Row operations : R_2 + R_1   &   R_3 + 2*R_1

\left[\begin{array}{ccccc}1&2&-3&1&1\\0&1&1&0&7\\0&0&1&1&3\end{array}\right]\\

corresponding equations are:

X_1 + 2*X_2 - 3*X_3 + X_4 = 1

X_2 + X_3  = 7

X_3 + X_4 = 3

Free parameter : X_4 = a , then:

X_3 = 3 - a

X_2 = 4 + a

X_1 = 1 - a + 3*(3 - a) - 2*(4 + a) = 2 - 6 a

4 0
4 years ago
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