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netineya [11]
4 years ago
5

A polynomial is factored using algebra tiles. An algebra tile configuration. 0 tiles are in the Factor 1 spot and 0 tiles are in

the Factor 2 spot. 8 tiles are in the Product spot in 2 columns with 4 rows: 1 is labeled + x squared, 1 is labeled + x, the 3 tiles below + x squared are labeled negative x, and the 3 tiles below the + x tile are labeled negative. What are the factors of the polynomial? (x − 1) and (x + 3) (x + 1) and (x − 3) (x − 2) and (x + 3) (x + 2) and (x − 3)

Mathematics
1 answer:
tino4ka555 [31]4 years ago
8 0

Answer:

The factors of the polynomial are:

(x + 1) and (x - 3).

Step-by-step explanation:

Consider the image attached.

The upper tiles shows: (x + 1)

And the left tiles shows: (x - 3)

So, the factors of the polynomial are:

(x + 1) and (x - 3).

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dmitriy555 [2]
The answer to the question

5 0
3 years ago
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Suppose X and Y are random variables with joint density function. f(x, y) = 0.1e−(0.5x + 0.2y) if x ≥ 0, y ≥ 0 0 otherwise (a) I
Hatshy [7]

a. f_{X,Y} is a joint density function if its integral over the given support is 1:

\displaystyle\int_{-\infty}^\infty\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=\frac1{10}\int_0^\infty\int_0^\infty e^{-x/2-y/5}\,\mathrm dx\,\mathrm dy

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so the answer is yes.

b. We should first find the density of the marginal distribution, f_Y(y):

f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\frac1{10}\int_0^\infty e^{-x/2-y/5}\,\mathrm dy

f_Y(y)=\begin{cases}\dfrac15e^{-y/5}&\text{for }y\ge0\\\\0&\text{otherwise}\end{cases}

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For the other probability, we can use the joint PDF directly:

P(X\le5,Y\le8)=\displaystyle\int_0^5\int_0^8f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy=1+e^{-41/10}-e^{-5/2}-e^{-8/5}

which is about 0.7326.

c. We already know the PDF for Y, so we just integrate:

E[Y]=\displaystyle\int_{-\infty}^\infty y\,f_Y(y)\,\mathrm dy=\frac15\int_0^\infty ye^{-y/5}\,\mathrm dy=\boxed5

5 0
3 years ago
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Answer:

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The slope of a line in form ax+by=c is -a/b
the yint of the line is c/b


so

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6 0
3 years ago
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Can someone help me with this??!!
WARRIOR [948]

Answer:

68

Step-by-step explanation:

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