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Nostrana [21]
3 years ago
5

I REALLY NEED HELP LIKE ASAP

Mathematics
2 answers:
Akimi4 [234]3 years ago
7 0

1. The square on the inside is 8 x 8 = 64

2. The triangle's area is 8x9x1/2= 72 x 1/2 = 36

3. there are 4 triangles so 36 x 4 = (or 72 x 2 ) = 144 :)

lakkis [162]3 years ago
4 0

Answer:

MAKE GUY ABOVE ME BRAINLIEST YOU CAN NOW JUST CLICK THE CROWN

Step-by-step explanation:

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A school paid $31.25 for each calculator.
Sonja [21]

Answer:

500/31.25=16

Step-by-step explanation:

The school bought 16 calculators

4 0
2 years ago
2t+8 &gt; -4 (t+1)<br> THE &gt; HAS A LIL LINE UNDER IT :)<br> &gt; = ____<br> _
lara31 [8.8K]
2t + 8 ≥ -4(t+1)

PEMDAS

2t + 8 ≥ -4t - 4

2t + 12 ≥ -4t

12 ≥ -6t

-2 ≤ t
7 0
3 years ago
A store owner offered a 25% discount off the regular price of a pair of shoes. The amount of the discount is $4.
m_a_m_a [10]

Answer:

D

Step-by-step explanation:

25% of 16 is 1/4x16=4, which leaves D as as your answer

3 0
3 years ago
Read 2 more answers
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
The ordered pair(5,-3) is a solution to which of the following inequalities?
Dmitrij [34]

A plumber worked 26 hours a week for half a year. If his hourly wage was $40, how much did he earn during this time period?

<span> <span>A.</span>$1040</span><span> <span>B.</span>$27,040</span><span> <span>C.</span>$54,080</span><span> <span>D.</span><span>$520</span></span>
7 0
3 years ago
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