Remark
If the lines are parallel, there are no solutions to the system of equations. Start with the equation you know the most about.
x + 6y = 7 Subtract x from both sides
x - x + 6y = 7 - x Combine
6y = - x + 7 Switch and divide by 6
y = -x / 6 + 7/6
The general equation for a line is y = mx + b where m is the slope of the line.
m = - 1/6
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Now look at the second equation
10ay - 5x = 32 Add 5x to both sides
10ay = 5x + 32 Divide by 10a
y = (5/10a)x + 32/(10a)
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Now you must make
5/10a = - 1/6 Cross Multiply
5* 6 = - 10a * 1
30 = - 10a Divide by - 10
a = 30 / - 10
a = - 3
So these two equations will have no solution when a = - 3
Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior: FALSE
<h3>
What is a sophomore?</h3>
- A sophomore in the United States is a student in their second year at an educational institution, usually a secondary school or a college or university, but also other types of post-secondary educational institutions.
- A sophomore in high school is equivalent to a tenth-grade or Class-10 student.
- In sports, a sophomore is a professional athlete in their second season.
As in the description, it is given that a sophomore in high school is equivalent to a tenth-grade or Class-10 student.
So, the above-given statement becomes false as it says that every student is a sophomore but the class has juniors and seniors.
Therefore, the statement "suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior" is FALSE.
Know more about sophomore here:
brainly.com/question/23382435
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The complete question is given below:
Suppose that every student in a discrete mathematics class of 25 students is a sophomore, a junior, or a senior. Is the following statement true or false:
"The course must have at least five sophomores, or at least 20 juniors, or at least 10 seniors."
Answer:
Step-by-step explanation:
Given
-- Leading coefficient
Required
Determine the polynomial
Represent the zeros with a, b and c.
Such that
The polynomial is:
Open bracket
Hello, I Am BrotherEye
Answer:
Median = 46.5
Minimum = 32
Maximum = 62
Lower quartile = 38
Upper quartile = 59
Step-by-step explanation:
Before we can proceed to solving any of these, it is best you arrange your data first from least to greatest
32 34 37 39 41 45 48 53 58 60 61 62
First we have the median. The Median is the middle value. In this case we an even number of data, which is 12 data points. The middle value of the data would be found in between the 6th and 7th data point:
45 and 48
To get the middle value, you need to solve for the value that is in the middle of 45 and 48 by getting the sum of both numbers and dividing it by two.
45 + 48 = 93
93 ÷ 2 = 46.5
The minimum and maximum value is merely the least and greatest number.
Here we have:
Minimum = 32
Maximum = 62
To get the lower and upper quartiles, just remember that quartiles divide the data into 4 equal parts. All you need to do is find the value that is in between each quarters of the data:
Q1 (Lower) Q2(Median) Q3(Upper)
32 34 37 | 39 41 45 | 48 53 58 | 60 61 62
Like the median, we will find the value that comes in between each quarter.
Q1
37 + 39 = 76
76 ÷ 2 = 38
Lower quartile = 38
Q3:
58 + 60 = 118
118 ÷ 2 = 59
Upper quartile = 59
