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liberstina [14]

3 years ago

5

(Please help, I will mark brainliest to the most accurate answer)

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

r=41/2

Step-by-step explanation:

The radius of a circle is always half it's diameter. In this circle, the diameter is 41 centimeters, so the radius would be half of that- which is 41/2 or 20.5 cm.

Hope this helps!

Levart [38]3 years ago

5 0

Answer:

<em>Hello There the correct answer is r=41/2 </em>

<h2> Explanation:</h2>

All you have to do is divide the diameter, in this case 41, by 2 because the radius of the circle is half of the diameter. So, the answer would be 20.5 cm Hope It Helps!

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pashok25 [27]

<h3>log [ (√3)(2 - x)/(3x) ] = log (2 - x) - ¹/₂ log 3 - log x</h3>

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x$

$\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

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