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3 years ago

Betsy is buying topsoil for the flower bed shown below.

Mathematics

1 answer:

astra-53 [7]3 years ago

6 0

Answer:

The correct answer is B. 3 bags

Correct statement, question and image:

Betsy is buying topsoil for the flower bed shown below (image attached)

One bag of topsoil covers 20 square meters.

How many bags of topsoil does Betsy need to cover her flower bed?

A 2 bags

B 3 bags

C 4 bags

D 5 bags

Source:

Previous question that can be found at brainly

Step-by-step explanation:

1. Let's find the area of the triangle:

Area = (Base * Height)/2

Area = (20 * 6)/2

Area of the flower bed = 60 m²

2. Now, let's calculate the number of bags of topsoil Betsy needs to cover her flower bed:

Number of bags = Area of the flower bed/Area covered by a bag of topsoil

Number of bags = 60/20

Number of bags = 3

The correct answer is B. 3 bags

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I need help I can’t cuaet understand this

Gwar [14]

Answer:

B, 140

Step-by-step explanation:

Alright so if you know to do volume this should be a breeze!

First off what you want to do is find the volume of the outside prism.

V=whl=4·5·8=160

160

Then find the smaller prisms volume.

V=whl=1·5·4=20

Minus the smaller from the bigger

160-20=140

The answers B!

7 0

3 years ago

In AVWX, XV W X and mW - 27°. Find m_X.

SashulF [63]

Answer:

m<X = $126^{o}$

Step-by-step explanation:

From the given isosceles triangle, we have;

<W and <V as the base angles

So that,

m<W = m<V = 27 (base angles of an isosceles triangle are equal)

Thus,

m<X + m<V + m<W = 180 (sum of angles in a triangle)

m<X + 27 + 27 = 180

m<X + 54 = 180

m<X = 180 - 54

= 126

m<X = $126^{o}$

8 0

3 years ago

Suppose y = 2x + 1 , where x and y are functions of t. (a) if dx/dt = 6, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find d

evablogger [386]

$y=2x+1\\\\\dfrac{dy}{dt}=2\dfrac{dx}{dt}$

(a) For dx/dt=6, dy/dt = 2·6 = 12

(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1

_____

The value of x is irrelevant for this question.

=====

If your function is 2^x +1 or 2^(x +1), it needs to be written as such. The answer above applies to the function given.

7 0

3 years ago

Find the range for the given domain: {-2, -1, and 0} and the function is y= 3x^2

likoan [24]

Answer:

{0, 3, 12}

Step-by-step explanation:

Put the domain values in the function and evaluate. The result is the range values.

y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}

For the given domain, the range is {0, 3, 12}.

_____

Additional comment

Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.

6 0

3 years ago

Fewer young people are driving. In 1983, 87% of 19-year-olds had a driver’s license. Twenty-five years later (in 2008) that perc

Dima020 [189]

Answer:

a) $ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019$

b) $ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245$

c) On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of $\hat p$ the margin of error change for part a and b.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.96$

If we replace the values into equation (a) for 1983 we got:

$ME=1.96\sqrt{\frac{0.87 (1-0.87)}{1200}}=0.019$

Part b

Since is the same confidence level the z value it's the same.

If we replace the values into equation (a) for 2008 we got:

$ME=1.96\sqrt{\frac{0.75 (1-0.75)}{1200}}=0.0245$

Is the margin of error the same in parts (a) and (b)? Why or why not?

On this case it's not the same since the proportion estimated for 1983 it's different from the proportion estimated for 2008. So since the margin of error depends of $\hat p$ the margin of error change for part a and b.

3 0

4 years ago