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KIM [24]
2 years ago
8

What is the solution of the linear equation (4−5) − (2+3) = (7−6)? * pls fast

Mathematics
1 answer:
maxonik [38]2 years ago
4 0

Answer:

no solution

Step-by-step explanation:

1.4-5-2-3=7-6

2.-1-2-3=7-6

3.-3-3=7-6

4.-6=7-6

5.-6=1

6.since -6=1 is false, there's no solution

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A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at ra
Soloha48 [4]

Answer:

P(M4\ n\ V) = 2.083\%

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

n(S) = 20

The outcomes of multiples of 4 is:

M4= \{4,8,12,16,20\}

n(M4) = 5

So, the probability of multiples of 4 is:

Pr(M4) = \frac{5}{20}

Pr(M4) = \frac{1}{4}

The sample size of PENNSYLVANIA is:

n(S) = 12

The outcome of V is:

n(V) = 1

So, the probability of V is:

P(V) = \frac{1}{12}

So, the required probability is: P(Multiple of 4 and V)

P(M4\ n\ V) = P(M4) * P(V)

P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}

P(M4\ n\ V) = \frac{1}{48}

P(M4\ n\ V) = 0.02083

Express as percentage

P(M4\ n\ V) = 0.02083 * 100\%

P(M4\ n\ V) = 2.083\%

4 0
3 years ago
6.1 is 1/3 of what?<br> Please help ASAP!
murzikaleks [220]

Answer:

18

Step-by-step explanation:

Round 6.1 down to 6. If you divide 18 by 3 you get 6.

Therefore, 6 is one third of 18.

6 0
2 years ago
Read 2 more answers
How do you write -4 1/5 as an improper fraction
jekas [21]
-21/5

Multiply 4 and 5, add 1
4 0
3 years ago
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Cion
Sidana [21]

Answer:

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Step-by-step explanation:

just add the recurring bar on top of the 3 and it should be correct

6 0
1 year ago
A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to
Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916

B) Here X is Bin (8, 0.1)

P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488

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P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319

3 0
3 years ago
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