Can someone help me please
2 answers:
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The 2-point form of the equation of a line is
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3
Written as a function, it is
.. f(x) = (2/3)x +3
.. y = (y2 -y1)/(x2 -x1)*(x -x1) +y1
For your points (x1, y1) = (0, 3) and (x2, y2) = (3, 5), this is
.. y = (5 -3)/(3 -0)*(x -0) +3
.. y = (2/3)x +3
Written as a function, it is
.. f(x) = (2/3)x +3
Student is wrong An exterior angle of a triangle can be adjacent to the right angle of a right triangle, so an exterior angle can be a right angle.
<h3>What is exterior angle?</h3>The Exterior Angle is the angle between any side of a shape, and a line extended from the next side.
The student make an error he states that the exterior angle of a triangle can never be a right angle.
The correct answer will be option D that is An exterior angle of a triangle can be adjacent to the right angle of a right triangle, so an exterior angle can be a right angle.I have also attached the diagram of the triangle for better understanding.
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